Originality-utility trade-off within creative
solutions to the Alternative Uses Task.
Lois van Vliet 10438033
Mentored by Claire Stevenson Bachelor thesis, University of Amsterdam
02-07-2016
Abstract
The aim of this study was to examine the originality-utility trade-off within creative solutions to the alternative Uses Task (AUT) and how originality and utility were related to creativity. Both experts and participants rated the responses from the AUT for originality, utility and creativity. A main
effect for experts ratings has been found between originality and utility; the
originality-utility trade-off. Participants did not show this trade-off. Next, it was found that originality
and utility were good predictors of creativity. Utility and creativity showed a small partial
correlation while originality and creativity showed a high correlation. This indicates that
originality plays a bigger part within the definition of creativity than utility.
Creativity remains a mysterious phenomenon. How innovative ideas are generated
or how humans come up with new solutions is complex and intriguing (Hennesy and
Amabile, 2010). However, how can creativity be measured? In this study it is attempted to
measure creativity by exploring its two basic characteristics in divergent thinking tasks.
The definition of creativity has been a subject of debate for a while now. According
to Stevenson, Kleibeuker, Drue and Crone (2014), creativity is seen as the ability to generate
ideas, solutions or insights that are novel and executable. While Besemer and O’Quin
(1987) were more concentrated on novelty, resolution (if the product is useful), elaboration
and synthesis (if the product is complex and well-crafted). Stein (1953) stated that creative
work is a novel work that is accepted as useful or satisfying by a group of people in some
point in time. Two main components came back in each interpretation of creativity:
originality and utility. An original idea is novel and personal. It is a vital characteristic of
creativity; when a solution or idea is not novel it will not be considered creative. An useful
or appropriate idea is executable and effective. For example; two creative alternative
solutions for a brick are: a parachute or a doorstop. The first one not useful, while using a
brick as a doorstop is useful. There is no use in thinking of solutions or ideas that can’t be
executed. So an original idea most be useful to be creative. Therefore, utility is next to
originality a vital characteristic. From these characteristics the following definition used and
examined in this paper is: a creative idea must be a novel idea that is also useful and
effective for a group of people.
originality and utility. This interaction can be explained with the example mentioned above.
Two alternative uses for a brick are; a doorstop or a parachute. A doorstop is useful,
however not original. A brick used as a parachute is original, nonetheless not useful. This
example indicates that there is a trade-off between originality and utility. Whenever an idea
is more original, the less appropriate or useful it becomes and vice versa. This negative
correlation is highly intriguing and can be compared to another known observation:
speed-accuracy trade-off.
The speed-accuracy trade-off is an important notion from reaction time research of
response times on test items (Van der Linden, 2007). This notion indicates that the fraction
of erroneous responses rises towards a lower reaction time. This means that when a subject
has little time, there is a greater possibility to give an inaccurate answer then when the
subject has more time (Schouten and Bekker, 1967; Van der Linden, 2007). Figure 1
illustrate the speed-accuracy trade-off.
Even though this trade-off is about speed and accuracy, it is a fascinating idea that,
instead of speed and accuracy, there could be a originality-utility trade off. Like the example
with the brick, the more original an idea is, the lower the utility is. Thus, theoretically the
existence of this trade-off is real within the definition of creativity.
The measurement of creativity and the measurement of the correlation between
originality and utility, is another subject of debate within the field of creativity. Basadur,
Runco and Vega (2000) argued that these discussions existed due to different processes
involved in creativity. Two different processes were described: divergent thinking and
convergent thinking. Convergent thinking is the mental process where a subject has to
generate or choose one idea (Gilhooly, 2007; Sivlia, 2015). Divergent thinking is the mental
process where a subject has to generate as many solutions or ideas as they can (Runco and
Acar, 2012; Silvia, 2015; Gilhooly et al, 2007). These different processes ask for different
kind of tasks and measurements. Divergent thinking tasks are considered good measures of
creativity (Silvia, 2015; Runco, 1993; Runco and Acar, 2012). It is a process that widens
thought and that leads to many responses (Silvia, 2015). Stated that divergent thinking is
the marker of creativity (Silvia, 2015), these tasks were used in this study.
There are different kind of divergent thinking tasks where responses are often
evaluated with fluency, originality and flexibility (Runco, 1993; Stevenson et al, 2014;
Ottenmiller et al, 2014; Gilhooly et al, 2007). Many studies do not include a measure of
appropriateness or utility when implementing divergent thinking tasks, despite the fact that
utility is considered a basic characteristic in the standard definition of creativity (Ottenmiller
characteristics is neglected. Hence, even though creativity and novelty have been examined
before, utility was never a part of these analyses.
To measure originality and utility an alternative uses task (AUT) was done. The AUT is
a typical divergent thinking task, where subjects have to generate as many possible
alternative uses for familiar objects (Ottenmiller et al,2014; Stevenson et al, 2014). The AUT
scores yield various measures for creative responses. Originally this task was made to
measure originality, fluency and feasibility (Mumford, 2001; Ottenmiller et al, 2014;
Stevenson, 2014) not utility.
Since, in this study the correlation between originality an utility
were examined, the responses were rated by their usefulness/appropriateness as well.
Giving previous findings, it was expected that the originality-utility trade-off exists
within the alternative uses task (Stevenson, in press, 2014). Ideas that will score high on
originality will score low on utility. It was also expected that originality and utility are good
predictors for creativity.
Method
Participants
The sample comprised 36 participants (M
age= 29.12, SD = 12.9, range = 16- 61 years,
74 % females). All participants were recruited through the University of Amsterdam
research system and trough contacted acquaintances. All participants provided informed
consent. All procedures were approved by the Internal Review Board of the University of
Amsterdam Institute of Psychology. After the study, two gift cards were raffled.
The data was gathered in one week. There were two drop-outs. The number of
subjects used in statistical analyses was 34.
Material
Alternative uses task (AUT). Participants administered a Dutch version of the
computerized AUT (Getzels & Jackson, 1962; Guilford, 1967; Stevenson et al, 2014).
Participants were given the name of an object and they were asked to came up with as
many alternative uses for the object as possible within a 2 min time period (Stevenson et al,
2014). For example, with the target item ‘brick’, a use as ‘doorstop’ might be produced by a
participant. Eight common objects were used in this experiment: brick, fork, paperclip,
towel, book, belt, stick and can. These objects were viewed in this specific order. This order
was equal for each participant.
AUT is traditionally scored for fluency, originality and flexibility. Considering the
standard definition of creativity, originality, utility and creativity were measured. All were
rated on a 10 point scale ( from 1 = ‘not original/useful/creative’ to 10 = ‘very
original/useful/creative’). As well as participants as three experts rated their answers.
The verbal fluency task. With the verbal fluency task, participants were administered
to generate as many animals or jobs as possible within a 2 min time period (Troyer &
Moskovitch & Winocur, 1997). These task was administered as distraction. Hence, these
responses were not taken into account for the analysis
Procedure
After the participants signed the informed consent they started the experiment. The
experiment consisted of four parts.
1. The participants started with the AUT. The items were presented in a specific order:
brick, fork, paperclip, towel, book, belt, stick and can. After each object the
participants could take a break.
2. After the AUT , the participants had to choose their two most creative solutions for
each item. An example is seen in Figure 2.
Figure 2. An example a selection from one participant for the object book. The
participant had to choose their top two.
3. As a distraction the participants solved two verbal fluency tasks for which they were
asked to think of as many animals or jobs as possible within a 2 minute timeframe.
4. The final task consisted of rating responses on originality, utility and creativity. It was
a 10-points scale, 1 = no originality/utility/creativity and 10 = very
original/useful/creative. The participants were provided with the definitions for
usefulness and originality. For creativity, the participants were asked to use their
own definition. For each item four standard responses were chosen by the experts.
Each participant had to rate these four responses plus their own top two responses.
An example for these ratings of responses on brick is shown in Figure 3.
Figure 3: example of response ratings for brick. The standard responses and the top two that
were given by a participant were on the left.
Consensual assessment technique
After all responses were gathered, all responses were rated by three experts. The
same scales were used as the ratings of the participants. Hence , 1 = no
originality/utility/creativity and 10 = very original/useful/creative. To reduce bias and
subjectivity there were guidelines for the experts. First, originality was obtained using the
frequency count for each response. A response that was often mentioned by different
participant was rated low, while responses that were unique were rated high. Second, utility
was obtained by rating the plausibility and sensible use. Third, creativity was obtained by
following the standard definition: a creative idea must be a novel idea that is also useful and
effective for a group of people. Finally for each object, all responses must be rated in a
specific order. All responses were first rated by their originality, second utility and last
creativity. Ratings on the other components were hidden. In such manner bias could been
reduced.
Inter-rater reliability. Inter-rater reliability for the AUT response coding was
established among three experts. R-package irr was used. Agreement and ‘oneway’ was
coded for each response category: creativity, originality and utility. Inter-rater reliability was
low; the ICC was respectively 0.33, 0.47 and 0.227.
Statistical analyses
Correlational study. First, a correlation test between originality and utility ratings,
according to the expert panel, was done. For this correlation test all items and all their
responses were used. Thereafter, the same correlation was calculated for each item
separated.
Multiple linear regression. A multiple linear regression was done for the expert
ratings on creativity, originality and utility. Creativity was the dependent variable. Originality
and utility were the independent variables. The next regression was analyzed:
Creativity = originality + utility + error.
First, this regression was executed for all items and responses. Thereafter, the regression
was executed for all items separately. Together with these regressions, the partial
correlation was calculated. These correlation was calculated with the R-package ppcor.
ANOVA. To compare different participants with different creativity levels to check if
the most creative participants indeed score high on originality and utility, the mean scores
on creativity for each participant was calculated. Based on these scores the participants
were classified into five groups. These five groups are presented in Table 3. To test whether
these groups differ for creativity, an ANOVA was executed.
Explorative study. Finally the ratings of all participants were examined. This analysis
consisted of calculating correlations between originality and utility. This way, the trade-off
could be studied according to the participants. Following, a regression analysis had been
done to have a better understanding of how participants think about creativity compared to
originality and utility. Again, creativity was the dependent variable and originality and utility
were the independent variables. Similarly to the expert ratings, the correlational study and
the regression analysis were done for each item separately.
Results*
Correlational study. To investigate the originality-utility trade-off, a correlation test
has been done to view how originality and utility were associated.
First, the trade-off overall the ratings was examined. There was a correlation found in the
expected direction, r = - 0.43 , t(1768) = -20.04, p < .05. This correlation is presented in
Figure 4. This figure visualize that when a solution is more original, it is less useful.
Figure 4. Negative linear correlation between utility and originality, r = 0.43 , t(1768) =
-20.0374, p < .05.
Second, the originality-utility trade-off for each item was calculated separately. The
visual representation of these analysis are seen in Figure 5. The correlation between
originality and utility differed somewhat per item and ranged from -0.10 to -0.70. As can be
seen in Figure 5 ‘paperclip’ had the weakest correlation and ‘belt’ the strongest. All
correlations were significant, as shown in Table 1. All correlations were in the expected
direction. This indicates that within every item an originality-utility trade-off is viewed.
Figure 5. Visual representation of the correlation between utility and originality for each
item separated.
Multiple regression. A multiple regression was applied to see how well originality and
utility predicted creativity. Creativity was the dependent variable. Utility and originality
were the independent variables. The regression was analyzed in the next form:
Table 1. Correlations between originality and utility for each item separated.
Originality and utility were good predictors for creativity, R
2= 0.60, F(2,1768) = 1368, p <
.05. 60 percent of differences in creativity could be explained by originality and utility. The
regression formula associated with these results were:
Creativity = 0.63 * originality + 0.20 * utility + 0.10
A partial correlation was calculated to examine to what extend this regression was
caused by originality and utility. Originality had the strongest partial correlation, r = 0.77 (p <
.05) , compared to utility, r = 0.327 ( p < .05). This means that originality correlated with 0.77
to creativity, considered the effect of utility removed. Utility on the other hand, correlated
with 0.32 to creativity, while the effect of originality was removed. Hence, originality
Correlation
t-value
P-value
Brick
-0.45
t(209) = -7.24
< .05
Can
-0.41
t(204) = -6.43
< .05
Book
-0.44
t(216) = -7.23
< .05
Towel
-0.26
t(282) = -4.48
< .05
Paperclip
-0.19
t(188) = -2.67
< .05
Belt
-0.70
t(199) = -13.76
< .05
Stick
-0.46
t(247) = -8.12
< .05
Fork
-0.39
t(208) = -6.08
< .05
Figure 6. A visual representation of how creativity, originality and utility are connected.
The previous results are summarized in Figure 6. This 3d plot showed that the data
indicates that there was a relation between originality and utility, originality and creativity,
nonetheless between originality and creativity there was a weak relation; the points were
spread.
The second part of this regression analyses consisted of calculating the originality
slopes and utility slopes for each item separately. These regression analyses and the
corresponding partial correlations are viewed in Table 2. The slopes for originality ranged
from 0.45 to 0.73 with partial correlation between 0.66 and 0.84. The slopes for utility
ranged from 0.08 to 0.33 with corresponding partial correlations between 0.15 to 0.53. It
can be concluded that originality had more influence on the prediction of creativity, than
Table 2. Regression coefficients and partial correlations for each item separately. The regression line is formed by: creativity = originality + utility + error. The partial correlation consisted of calculated correlations between originality and creativity, and utility and creativity.
Creativity = originality + utility + error Partial correlation Originality Utility
Inter-cept F(df) R
2
p-value Originality and creativity
p –
value Utility and creativity p-value Brick 0.57 0.19 0.47 F(2, 208) = 147.4 0.58 < .05 0.76 < .05 0.38 <.05 Fork 0.56 0.10 0.71 F(2,207) = 187.5 0.64 < .05 0.79 < .05 0.19 < .05 Paperclip 0.45 0.33 0.17 F(2,187) = 91.33 0.49 < .05 0.66 < .05 0.53 < .05 Towel 0.62 0.19 0.05 F(2,281) = 111.7 0.44 < .05 0.66 < .05 0.29 < .05 Book 0.73 0.20 -0.56 F(2,215) = 262.1 0.71 < .05 0.84 < .05 0.37 < .05 Belt 0.68 0.22 -0.35 F(2,198) = 197.5 0.66 < .05 0.78 < .05 0.38 < .05 Stick 0.73 0.08 0.18 F(2,247) = 355.6 0.74 < .05 0.84 < .05 0.15 < .05 Can 0.63 0.27 0.04 F(2,203) = 175 0.63 < .05 0.80 < .05 0.43 < .05
ANOVA. For a better understanding on how creativity is connected to originality and
utility an ANOVA was executed. All participants were classified in groups of five based on
their mean score for creativity. Considering that these analyses were for exploring creativity
within participants, there were no specific rules for the group classification. The groups
were classified in a way that the size of the groups were close to equal. For each participant
a mean score was calculated for creativity, originality and utility. In Table 3 the group size
and their mean score for creativity was presented.
A one-way ANOVA was executed to check whether the groups significantly differ for
creativity. Creativity was the dependent variable in this analyses. Creativity did significantly
differ between the different groups F(4,29) = 99.62, p< 0 .05. A visual presentation of this
analyses is given in Figure 7. Figure 7 shows the different scores for each participant in a
particular group. As seen, these groups differ for creativity.
Table 3. Group classification, means and group size.
Group
Mean creativity
N
Group 1
<3.5
3
Group 2
> 3.5 and < 4.0
8
Group 3
> 4.0 and < 4.25
10
Group 4
> 4.25 and <4.5
7
Figure 7. Creativity mean scores of participants in each group.
After dividing participants in different groups, an originality utility plot was made
(Figure 8). In Figure 8 different colors represent the different groups. A trade-off is seen in
this Figure. Hence, the least creative participants score highest on utility and lowest on
originality, while the most creative participants scores high on originality and intermediate
for Utility. It can be stated that the more creative a participant is, the more original their
ideas are, that are sufficient to use.
Figure 8. Participants in different groups, but with their own means on originality and utility.
Furthermore for each participant a creativity mean score was calculated for each
item. These points are plotted in Figure 9. The participants remained in the same group they
have been previously assigned to. Every color in Figure 9 still represent a different group.
The trade-off was more present in this Figure compared to the previous one. More creative
participants had high scores for originality and intermediate utility scores. It can be stated
that creativity is more connected to originality than utility.
Figure 9. Participants in different groups, but with their own means on originality and utility
for each item.
Exploratory study. In the exploratory study the participant ratings were used. Each
participant rated four standard responses for creativity, originality and utility. These ratings
were examined.
First the originality-utility trade-off was examined overall the data (Figure 10). Figure
10 shows the correlation of this connection. As can be seen, there is no significant
correlation between the two components ( r = - 0.01, F (1055) = -.37, p = -.71). This indicates
that participants do not think that there is a correlation between these two concepts.
Figure 10. Originality versus utility overall data, according to participants ( r = - 0.01, F
(1055) = --.37, p = -.71).
Linear regression. After the correlation test a multiple regression analysis was done.
The dependent variable was creativity and the independent variables were originality and
utility. According to the participants, originality and utility were good predictors for
creativity. The next regression was found:
Creativity = 0.71 * originality + 0.18 * utility + 0.32
with R
2= 0.56, F( 2 , 1054) = 683.7, p < .05. It can be implied that 56 percent of differences
in creativity can be explained by originality and utility. A partial correlation was calculated
to examine to what extend this regression is caused by originality and utility. Originality had
the strongest partial correlation, r = 0.74, p < .05, compared to utility, r = 0.30, p < . 05.
After using all participants ratings for each item, the originality-utility relation was
examined for each item separately. This trade-off was visualized in Figure 11. As viewed in
this Figure, there seems to be no correlation between originality and utility in different
items. This unexpected result implied that participants don't see an association between
originality and utility.
Furthermore, a regression analysis was done for each item separately. Similar to the
expert ratings; creativity was the dependent variable, originality and utility were the
independent variables. These regression analyses and the corresponding partial correlations
are viewed in Table 4.
Originality and utility were good predictors to creativity. The regression coefficients
for originality ranged from 0.61 to 0.86 with partial correlation between 0.63 and 0.81. The
regression coefficients for utility ranged from 0.10 to 0.27 with corresponding partial
correlations between 0.02 to 0.41. The only non-significant partial correlation was between
utility and creativity for the item ‘book’.
These results indicated that originality and utility were good predictors for creativity,
nevertheless originality had more influence on the prediction of creativity, than utility.
Table 4. Regression coefficients and partial correlations for each item separately according to the participants. The regression line is formed by: creativity = originality + utility + error. The partial correlation consisted of calculated correlations between originality and creativity, and utility and creativity.
Creativity = originality + utility + error Partial correlation
Originality Utility
Inter-cept F(df) R
2
p-value Originality and creativity
p –
value Utility and creativity p-value Brick 0.61 0.27 0.46 F(2, 135) = 59.45 0.46 < .05 0.63 < .05 0.41 <.05 Fork 0.72 0.18 0.41 F(2,129) = 81.98 0.55 < 0.05 0.73 < .05 0.28 < .05 Paperclip 0.63 0.19 0.93 F(2,124) = 60.1 0.48 < .05 0.68 < .05 0.27 < .05 Towel 0.73 0.17 0.29 F(2,129) = 86.2 0.56 < .05 0.75 < .05 0.28 < .05 Book 0.71 0.10 0.83 F(2,127) = 75.78 0.544 < .05 0.72 <.05 0.15 0.08 Belt 0.86 0.22 -0.76 F(2,130) = 129.4 0.66 < .05 0.81 < .05 0.40 < .05 Stick 0.80 0.12 0.24 F(2,131) = 112.5 0.63 < .05 0.78 < .05 0.02 0.021 Can 0.65 0.19 0.28 F(2,128) = 85.19 0.56 < .05 0.73 < .05 0.33 < .05
Discussion
The aim of the current study was to examine the originality-utility trade-off within
creative solutions to the Alternative Uses task (AUT) and how these variables were related
to creativity. To this end, participants were administered the AUT and the responses were
rated by an expert panel on originality, utility and creativity. Furthermore, participants rated
their own top two creative responses and a number of example responses on originality,
utility and creativity (Figure 3). Results from the expert panel indicated an originality-utility
trade-off. On top of that, results from both participants and the expert panel indicated that
originality an utility were good predictors of creativity.
As expected, the originality-utility trade-off was found for the expert ratings on all
items. To summarize: the more original an alternative solution was, the lower its usefulness.
This trade-off was too presented in each item, nevertheless the slope differed over different
items (Table 2). There were two outliers, ‘belt ‘ and ‘paperclip’. ‘Paperclip’ had a small slope
and ‘belt’ had a high slope. A reason for these findings could be their frequency in
present-day. It is easier to generate non-creative ideas for high frequency objects as compared to
low frequency objects (Forthman & Gerwi & Holling & Celik &strome & Lubart et all, 2014).
‘Paperclip’ was a low frequency object, what led to more idiosyncratic associations and thus
more original solutions that were both useful and useless. This led to lower slopes. ‘Belt’ on
the other hand, was a high frequency object. There were many associations, but many were
shared and banal associations (Forthman et all, 2014). This led to lesser original solutions
that were more useful. Thus, when an item is less frequent in present-day, little solutions
Another expected result was the goodness of fit of the regression model for
creativity, according to the expert panel. Creativity was predicted by originality and utility.
The creativity definition could be obtained from this regression. Originality had the highest
regression coefficient and partial correlation compared to utility. Thus, it was valid to define
originality as the vital characteristic; a new idea must especially be novel to be creative.
Utility had a small regression coefficient and a small partial correlation. This implied that
utility was not vital. Utility could be seen as an additional feature to creativity. This was
presented in Figure 6, between creativity an utility the points were spread compared to the
points between creativity and originality.
The goodness of fit of the regression model was an expected result for both
participant ratings as for expert ratings. Still there was a difference between the two groups.
Compared to the experts, for the participant the regression coefficient for originality was
higher and the regression coefficient for utility was lower. This indicated that participants
did recognize the importance for originality, nonetheless not for utility in creative thinking.
This could imply that definitions used outside the scientific community differ from
definitions inside the scientific community. For example, during the experiment multiple
participants commented that they did not know the difference between originality and
creativity. This statement was supported by the high regression coefficient (b = 0.71, r = 0.74
) compared to the regression coefficient according to experts ( b = 0.63, r = 0.77). It could be
stated that originality is closer connected to creativity according to the participants than it is
closer to creativity according to the experts.
This difference in use of definition for creativity and originality could have caused
one unexpected result; the missing originality-utility trade-off within participants. When
originality and creativity are as closely related as the participants think, usefulness could
have been already connected to originality. What led to an unknowingly influence off the
originality and utility ratings. This implies that a novel idea scored higher on originality when
it was also useful. Thus no trade-odd could be found.
Limitations
Some limitations of this study deserve mention and can be informative for future
research. First, the inter-rater reliability was low. This could have been caused by a slight
different scoring pattern. For example: If expert 1 scored consistently 1 point higher than
expert 2, after 1800 responses the ratings differ significantly for just originality, but the
fraction of utility and originality could still be the same. By using means scores, this fraction
is still present and the scores were more objective.
Another reason for these low inter-rater reliability and for the different results
between expert ratings and participant ratings, can be explained by intrinsic values. To
visualize this problem, Figure 12 shows the different ratings from different participants on
‘Yoga stone’ as an alternative use for ‘Brick’. Every dot represents another participant. It
can be concluded that different participants rated very differently. This could be explained
by different intrinsic values (Kasof, Chem, Himsel & Greenbemer, 2007). Kasof and his
colleagues demonstrated that an individual’s intrinsic values had a big influence on their
creative behavior. For example: participant A thought that the Yoga stone was very original,
nevertheless he did not think it would be comfortable and thus not useful. While participant
B already used a brick as a Yoga stone. Participant B would have rated the yoga stone as not
original but very useful. Participant C on the other hand never thought of using a brick as an
yoga stone, nevertheless thinks it could be very useful.
This example shows that even though the same definitions were used, still
participant A, B and C rated the yoga stone differently. To counter this, mean scores of the
responses could be calculated of the trade- off could be calculated for each person instead
for each item. By analyzing the trade-off for each person you can take the intrinsic values
into account and still examine the trade-off.
.
Another limitation of this study is about the calculated creativity means for each
participant. These means were calculated for every response the participant had. But even
the most creative participant responded with some standard answers: hit, throw, catch. Due
to these responses, creativity means were low. For next researches, these standard answers
Another manner to counter this is to focus on top two answers. This way, the standard
responses could be filtered out.
The last limitation that should be taken into account for future research is the
randomization of the items. In this study the items were in the same order for every
participant. For more objective results, these items should be random.
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Appendix A reflectieverslag
A. Omgang met de feedback
In mijn bachelor these project ging de omgang met feedback goed. Wanneer ik de feedback
niet begreep ben ik naar mijn begeleider gestapt zodat ik meer uitleg kon krijgen. De
feedback was daarnaast redelijk. De zaken die mijn begeleider had opgemerkt aan wat er
fout was, was ik het ook bijna altijd mee eens en heb het zo goed mogelijk aangepast.
B. Het project.
Het project ging qua communicatie erg goed. Ik ben goed begeleid door mijn gehele these
en kon altijd bij mijn begeleider terecht. Ook binnen het groepje konden we het goed met
elkaar vinden en voerde iedereen altijd wel de taken uit.
Het enige puntje waar het niet goed ging was de planning. Doordat in het begin het nog een
beetje onduidelijk was wanneer de deadlines waren begonnen we ook erg laat aan het
experimentele gedeelte van het onderzoek. Hierdoor heb ik de laatste maand ontzettend
veel stress ervaren.
Nog een puntje die ik zelf jammer vond, was dat ik uiteindelijk niet heb kunnen helpen bij
het programmeren van het experiment. Ik heb al een klein beetje een achtergrond in
programmeren en had het daarop leerzaam gevonden om het experiment te helpen
programmeren. Helaas door te weinig tijd, is dit niet gelukt.
C. Sterke en zwakke punten.
Sterke punten
Ik denk dat de sterke punten in mijn onderzoek de analyses zijn die ik heb gedaan. Ik heb
elke analyse zelf gecodeerd, waardoor ik zelf het overzicht had van wat er was gedaan en
hoe. Hierdoor heb ik alles goed kunnen interpreteren. Wat ook een sterk punt aan mijn
onderzoek is, is dat een originaliteit-utiliteit onderzoek nooit eerder is uitgevoerd. Dit is het
eerste onderzoek in deze richting, waardoor het een sterke wetenschappelijke relevantie
heeft.
Zwakke punten
De zwakke punten in mijn onderzoek zijn de beoordelingen van de experts en de
deelnemers. Hoewel er zoveel mogelijk is geprobeerd om een bepaalde mate van
objectiviteit aan te houden, zit er in het beoordelen toch een grote subjectieve factor. Dat is
een minpunt aan dit onderzoek.
Een ander zwakpunt is dat er niet dezelfde uitkomsten waren bij de participanten en de
experts.
Ethische aspecten.
Het experimentele gedeelte was ethisch verantwoord. We waren open naar onze
participanten toe, waardoor er van ethische problemen geen sprake was.
Appendix B, R-code
# analyse
# inlezen van alle bestanden + sorteren
# alle bestanden van julia baksteen1 = choose.files()
juliabaksteen = read.csv(baksteen1, header=T,sep = ";") order.baksteen<-order(juliabaksteen$autresponse_id) juliabaksteen <- juliabaksteen[order.baksteen,] blik2 = choose.files()
juliablik = read.csv(blik2, header=T,sep = ";") order.juliablik<-order(juliablik$autresponse_id) juliablik <- juliablik[order.juliablik,]
boek3 = choose.files()
juliaboek = read.csv(boek3, header=T,sep = ";") order.boek<-order(juliaboek$autresponse_id) juliaboek <- juliaboek[order.boek,]
juliaboek<-juliaboek[-c(254,255,256),] handdoek4 = choose.files()
juliahanddoek = read.csv(handdoek4, header=T,sep = ";") order.handdoek<-order(juliahanddoek$autresponse_id) juliahanddoek<-juliahanddoek[order.handdoek,] paperclip5 = choose.files()
juliapaperclip = read.csv(paperclip5, header=T,sep = ";") order.paperclip<-order(juliapaperclip$autresponse_id) juliapaperclip<-juliapaperclip[order.paperclip,]
juliapaperclip<-juliapaperclip[-c(229,230),]
riem6 = choose.files()
juliariem = read.csv(riem6, header=T,sep = ";") order.riem<-order(juliariem$autresponse_id) juliariem<-juliariem[order.riem,]
stok7 = choose.files()
juliastok = read.csv(stok7, header=T,sep = ";") order.stok<-order(juliastok$autresponse_id)
vork8 = choose.files()
juliavork = read.csv(vork8, header=T,sep = ";") order.vork<-order(juliavork$autresponse_id) juliavork<-juliavork[order.vork,]
# alle bestanden van isabella baksteen1 = choose.files()
isabaksteen = read.csv(baksteen1, header=T,sep = ";") order.baksteen<-order(isabaksteen$autresponse_id) isabaksteen <- isabaksteen[order.baksteen,]
blik2 = choose.files()
isablik = read.csv(blik2, header=T,sep = ";") order.isablik<-order(isablik$autresponse_id) isablik <- isablik[order.isablik,]
boek3 = choose.files()
isaboek = read.csv(boek3, header=T,sep = ";") order.boek<-order(isaboek$autresponse_id) isaboek <- isaboek[order.boek,]
handdoek4 = choose.files()
isahanddoek = read.csv(handdoek4, header=T,sep = ";") order.handdoek<-order(isahanddoek$autresponse_id) isahanddoek<-isahanddoek[order.handdoek,]
paperclip5 = choose.files()
isapaperclip = read.csv(paperclip5, header=T,sep = ";") order.paperclip<-order(isapaperclip$autresponse_id) isapaperclip<-isapaperclip[order.paperclip,]
riem6 = choose.files()
isariem = read.csv(riem6, header=T,sep = ";") order.riem<-order(isariem$autresponse_id) isariem<-isariem[order.riem,]
stok7 = choose.files()
isastok = read.csv(stok7, header=T,sep = ";") order.stok<-order(isastok$autresponse_id) isastok<-isastok[order.stok,]
vork8 = choose.files()
isavork = read.csv(vork8, header=T,sep = ";") order.vork<-order(isavork$autresponse_id) isavork<-isavork[order.vork,]
# ale bestanden van lois baksteen1 = choose.files()
loisbaksteen = read.csv(baksteen1, header=T,sep = ";") order.baksteen<-order(loisbaksteen$autresponse_id) loisbaksteen <- loisbaksteen[order.baksteen,]
blik2 = choose.files()
loisblik = read.csv(blik2, header=T,sep = ";") order.loisblik<-order(loisblik$autresponse_id) loisblik <- loisblik[order.loisblik,]
boek3 = choose.files()
loisboek = read.csv(boek3, header=T,sep = ";") order.boek<-order(loisboek$autresponse_id) loisboek <- loisboek[order.boek,]
handdoek4 = choose.files()
loishanddoek = read.csv(handdoek4, header=T,sep = ";") order.handdoek<-order(loishanddoek$autresponse_id) loishanddoek<-loishanddoek[order.handdoek,]
loishanddoek<-loishanddoek[-307,] paperclip5 = choose.files()
loispaperclip = read.csv(paperclip5, header=T,sep = ";") order.paperclip<-order(loispaperclip$autresponse_id) loispaperclip<-loispaperclip[order.paperclip,]
riem6 = choose.files()
loisriem = read.csv(riem6, header=T,sep = ";") order.riem<-order(loisriem$autresponse_id) loisriem<-loisriem[order.riem,]
stok7 = choose.files()
loisstok = read.csv(stok7, header=T,sep = ";") order.stok<-order(loisstok$autresponse_id) loisstok<-loisstok[order.stok,]
vork8 = choose.files()
loisvork = read.csv(vork8, header=T,sep = ";") order.vork<-order(loisvork$autresponse_id) loisvork<-loisvork[order.vork,]
# Per item niet goede antwoorden eruit halen, dan krijg je vervolgens de totale data. # baksteen
validbaksteen invalidbaksteen=c(NA) for (i in 1:length(validbaksteen)){ if (validbaksteen[i]!= 0){ invalidbaksteen = c(invalidbaksteen, i) }} invalidbaksteen
baksteen<-data.frame(isabaksteen[,1:8], loisbaksteen[,5:7], juliabaksteen[,5:7]) baksteen<-baksteen[-c(invalidbaksteen[2:length(invalidbaksteen)]),] # blikje validblik = isablik[,8]+loisblik[,8]+juliablik[,8] invalidblik=c(NA) for (i in 1:length(validblik)){ if (validblik[i]!= 0){ invalidblik = c(invalidblik, i) }} invalidblik
blik<-data.frame(isablik[,1:8], loisblik[,5:7], juliablik[,5:7]) blik<-blik[-c(invalidblik[2:length(invalidblik)]),] # boek validboek = isaboek[,8]+loisboek[,8]+juliaboek[,8] invalidboek=c(NA) for (i in 1:length(validboek)){ if (validboek[i]!= 0){ invalidboek = c(invalidboek, i) }} invalidboek
boek<-data.frame(isaboek[,1:8], loisboek[,5:7], juliaboek[,5:7]) boek<-boek[-c(invalidboek[2:length(invalidboek)]),]
validhanddoek = isahanddoek[,8]+loishanddoek[,8]+juliahanddoek[,8] invalidhanddoek=c(NA) for (i in 1:length(validhanddoek)){ if (validhanddoek[i]!= 0){ invalidhanddoek = c(invalidhanddoek, i) }} invalidhanddoek
handdoek<-data.frame(isahanddoek[,1:8], loishanddoek[,5:7], juliahanddoek[,5:7]) handdoek<-handdoek[-c(invalidhanddoek[2:length(invalidhanddoek)]),] # paperclip validpaperclip = isapaperclip[,8]+loispaperclip[,8]+juliapaperclip[,8] invalidpaperclip=c(NA) for (i in 1:length(validpaperclip)){ if (validpaperclip[i]!= 0){ invalidpaperclip = c(invalidpaperclip, i) }} invalidpaperclip
paperclip<-data.frame(isapaperclip[,1:8], loispaperclip[,5:7], juliapaperclip[,5:7]) paperclip<-paperclip[-c(invalidpaperclip[2:length(invalidpaperclip)]),] # riem validriem = isariem[,8]+loisriem[,8]+juliariem[,8] invalidriem=c(NA) for (i in 1:length(validriem)){ if (validriem[i]!= 0){ invalidriem = c(invalidriem, i) }} invalidriem
riem<-data.frame(isariem[,1:8], loisriem[,5:7], juliariem[,5:7]) riem<-riem[-c(invalidriem[2:length(invalidriem)]),]
# stok
invalidstok=c(NA) for (i in 1:length(validstok)){ if (validstok[i]!= 0){ invalidstok = c(invalidstok, i) }} invalidstok
stok<-data.frame(isastok[,1:8], loisstok[,5:7], juliastok[,5:7]) stok<-stok[-c(invalidstok[2:length(invalidstok)]),] names(employ.data)[3] <- 'firstday' names(stok)[11]<- 'creativity.1' names(stok)[14]<- 'creativity.2' # vork validvork = isavork[,8]+loisvork[,8]+juliavork[,8] invalidvork=c(NA) for (i in 1:length(validvork)){ if (validvork[i]!= 0){ invalidvork = c(invalidvork, i) }} invalidvork
vork<-data.frame(isavork[,1:8], loisvork[,5:7], juliavork[,5:7]) vork<-vork[-c(invalidvork[2:length(invalidvork)]),] names(stok) # --- mydata<-rbind(baksteen,blik,boek,handdoek,paperclip,riem,stok,vork) #--- # de analyses
# is er een verschil tussen de experts? # originaliteit
#ANOVA toets
originaliteit = data.frame(mydata$originality, mydata$originality.1, mydata$originality.2) utility = data.frame(mydata$utility, mydata$utility.1, mydata$utility.2)
creativiteit = data.frame(mydata$creativity, mydata$creativity.1, mydata$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteit = apply(originaliteit,1,mean) utility = apply(utility,1,mean)
creativiteit= apply(creativiteit,1,mean)
#--- # grafieken tegen elkaar uitzetten
old.par <- par(mfrow=c(1,1))
plot(originaliteit,utility , main = "Originality and utility overall", type = "p", xlab = "Originality", ylab = "Utility", col = 1, bg = 'white',pch = 19 )
abline(lm(originaliteit~utility)) cor.test(originaliteit, utility) fit fit<-lm(originaliteit~utility) summary(fit) # 3D Scatterplot library(rgl)
plot3d(utility,originaliteit,creativiteit,pch=19, cex = 2.5,NAcol = "grey", highlight.3d = TRUE, xlab = 'Utility', ylab= 'Originality', zlab = 'Creativity', cex.axis = 2.5)
fit<-lm(creativiteit~originaliteit+utility) summary(fit)
fit ?plot3d
# utility vs creativity
plot(utility,creativiteit,main = "creativity and utility", pch=19,type = "p", xlab = "Utility", ylab = "Creativiteit", col = "black")
abline(lm(creativiteit~utility)) fit2<-lm(creativiteit~utility) summary(fit2)
plot(originaliteit,creativiteit,las=1,main = "Originality and Creativity", pch = 19, type = "p", xlab = "Originality", ylab = "Creativity", col = "black")
abline(lm(creativiteit~originaliteit)) fit<-lm(creativiteit~originaliteit) summary(fit) fit #regressieanalyse #--- # originaliteit tegenover utility voor elk item #--- # baksteen
old.par <- par(mfrow=c(3, 3)) #baksteen
baksteen.originaliteit = data.frame(baksteen$originality, baksteen$originality.1, baksteen$originality.2)
baksteen.utility = data.frame(baksteen$utility, baksteen$utility.1, baksteen$utility.2)
baksteen.creativiteit = data.frame(baksteen$creativity, baksteen$creativity.1, baksteen$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteitbaksteen = apply(baksteen.originaliteit,1,mean) utilitybaksteen = apply(baksteen.utility,1,mean)
creativiteitbaksteen= apply(baksteen.creativiteit,1,mean) # grafieken tegen elkaar uitzetten
plot(originaliteitbaksteen,utilitybaksteen, pch = 19, main = "Brick", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor(originaliteitbaksteen,utilitybaksteen) (cor.test(originaliteitbaksteen, utilitybaksteen))
abline(lm(originaliteitbaksteen~utilitybaksteen),col = 2) lm(originaliteitbaksteen~utilitybaksteen)
fit3
summary(fit3)
# blikje
blik.originaliteit = data.frame(blik$originality, blik$originality.1, blik$originality.2) blik.utility = data.frame(blik$utility, blik$utility.1, blik$utility.2)
blik.creativiteit = data.frame(blik$creativity, blik$creativity.1, blik$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteitblik = apply(blik.originaliteit,1,mean) utilityblik = apply(blik.utility,1,mean)
creativiteitblik= apply(blik.creativiteit,1,mean) # grafieken tegen elkaar uitzetten
plot(originaliteitblik,utilityblik, pch = 19, main = "Can", type = "p", xlab = "Originality", ylab = "Utility", col = "black") cor(originaliteitblik,utilityblik) cor.test(originaliteitblik,utilityblik) abline(lm(originaliteitblik~utilityblik),col = 2) lm(originaliteitblik~utilityblik) summary(lm(originaliteitblik~utilityblik))
fit3<-lm(creativiteitblik ~ originaliteitblik + utilityblik) fit3
summary(fit3) # boek
boek.originaliteit = data.frame(boek$originality, boek$originality.1, boek$originality.2) boek.utility = data.frame(boek$utility, boek$utility.1, boek$utility.2)
boek.creativiteit = data.frame(boek$creativity, boek$creativity.1, boek$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteitboek = apply(boek.originaliteit,1,mean) utilityboek = apply(boek.utility,1,mean)
creativiteitboek= apply(boek.creativiteit,1,mean) # grafieken tegen elkaar uitzetten
plot(originaliteitboek,utilityboek, pch = 19, main = "Book", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor(originaliteitboek,utilityboek) cor.test(originaliteitboek,utilityboek)
lm(originaliteitboek~utilityboek)
summary(lm(originaliteitboek~utilityboek))
fit3<-lm(creativiteitboek ~ originaliteitboek + utilityboek) fit3
summary(fit3)
# handdoek
handdoek.originaliteit = data.frame(handdoek$originality, handdoek$originality.1, handdoek$originality.2)
handdoek.utility = data.frame(handdoek$utility, handdoek$utility.1, handdoek$utility.2) handdoek.creativiteit = data.frame(handdoek$creativity, handdoek$creativity.1,
handdoek$creativity.2)
# de gemiddeldes berekenen per variabele.
originaliteithanddoek = apply(handdoek.originaliteit,1,mean) utilityhanddoek = apply(handdoek.utility,1,mean)
creativiteithanddoek= apply(handdoek.creativiteit,1,mean) # grafieken tegen elkaar uitzetten
plot(originaliteithanddoek,utilityhanddoek, pch = 19, main = "Towel", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor(originaliteithanddoek,utilityhanddoek) cor.test(originaliteithanddoek,utilityhanddoek)
abline(lm(originaliteithanddoek~utilityhanddoek),col = 2) lm(originaliteithanddoek~utilityhanddoek)
summary(lm(originaliteithanddoek~utilityhanddoek))
fit3<-lm(creativiteithanddoek ~ originaliteithanddoek + utilityhanddoek) fit3
summary(fit3) # paperclip
paperclip.originaliteit = data.frame(paperclip$originality, paperclip$originality.1, paperclip$originality.2)
paperclip.utility = data.frame(paperclip$utility, paperclip$utility.1, paperclip$utility.2) paperclip.creativiteit = data.frame(paperclip$creativity, paperclip$creativity.1, paperclip$creativity.2)
# de gemiddeldes berekenen per variabele.
originaliteitpaperclip = apply(paperclip.originaliteit,1,mean) utilitypaperclip = apply(paperclip.utility,1,mean)
# grafieken tegen elkaar uitzetten
plot(originaliteitpaperclip,utilitypaperclip,pch = 19, main = "Paperclip", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor.test(originaliteitpaperclip,utilitypaperclip)
abline(lm(originaliteitpaperclip~utilitypaperclip),col = 2) lm(originaliteitpaperclip~utilitypaperclip)
summary(lm(originaliteitpaperclip~utilitypaperclip))
fit3<-lm(creativiteitpaperclip ~ originaliteitpaperclip + utilitypaperclip) fit3
summary(fit3)
# riem
riem.originaliteit = data.frame(riem$originality, riem$originality.1, riem$originality.2) riem.utility = data.frame(riem$utility, riem$utility.1, riem$utility.2)
riem.creativiteit = data.frame(riem$creativity, riem$creativity.1, riem$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteitriem = apply(riem.originaliteit,1,mean) utilityriem = apply(riem.utility,1,mean)
creativiteitriem= apply(riem.creativiteit,1,mean) # grafieken tegen elkaar uitzetten
plot(originaliteitriem,utilityriem, pch = 19, main = "Belt", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor.test(originaliteitriem,utilityriem)
abline(lm(originaliteitriem~utilityriem),col = 2) lm(originaliteitriem~utilityriem)
summary(lm(originaliteitriem~utilityriem))
fit3<-lm(creativiteitriem ~ originaliteitriem + utilityriem) fit3
summary(fit3)
# stok
stok.originaliteit = data.frame(stok$originality, stok$originality.1, stok$originality.2) stok.utility = data.frame(stok$utility, stok$utility.1, stok$utility.2)
stok.creativiteit = data.frame(stok$creativity, stok$creativity.1, stok$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteitstok = apply(stok.originaliteit,1,mean) utilitystok = apply(stok.utility,1,mean)
# grafieken tegen elkaar uitzetten
plot(originaliteitstok,utilitystok,pch = 19, main = "Stick", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor.test(originaliteitstok,utilitystok)
abline(lm(originaliteitstok~utilitystok),col = 2) lm(originaliteitstok~utilitystok)
summary(lm(originaliteitstok~utilitystok))
fit3<-lm(creativiteitstok ~ originaliteitstok + utilitystok) fit3
summary(fit3)
# vork
vork.originaliteit = data.frame(vork$originality, vork$originality.1, vork$originality.2) vork.utility = data.frame(vork$utility, vork$utility.1, vork$utility.2)
vork.creativiteit = data.frame(vork$creativity, vork$creativity.1, vork$creativity.2) # de gemiddeldes berekenen per variabele.
originaliteitvork = apply(vork.originaliteit,1,mean) utilityvork = apply(vork.utility,1,mean)
creativiteitvork= apply(vork.creativiteit,1,mean) # grafieken tegen elkaar uitzetten
plot(originaliteitvork,utilityvork, pch =19, main = "Fork", type = "p", xlab = "Originality", ylab = "Utility", col = "black")
cor.test(originaliteitvork,utilityvork)
abline(lm(originaliteitvork~utilityvork),col = 2) lm(originaliteitvork~utilityvork)
summary(lm(originaliteitvork~utilityvork))
fit3<-lm(creativiteitvork ~ originaliteitvork + utilityvork) fit3
summary(fit3)
# baksteen
old.par <- par(mfrow=c(1,1))
#analyse voor het maken van proefpersonen. Hierdoor zouden we kunnen kijken hoe verschillende personen dus hebben gescoord.
# eerste nemen we baksteen
baksteen.nu<-data.frame(baksteen$autresponse_id,baksteen$participant_fk, baksteen$ response,creativiteitbaksteen)
order.ppn.baksteen<-order(baksteen.nu$baksteen.participant_fk) baksteen.nu<-baksteen.nu[order.ppn.baksteen,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.baksteen <- data.frame( nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.baksteen = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(baksteen.nu)){ if (baksteen.nu[i,2]==ppn){
som = som + baksteen.nu$creativiteitbaksteen[i] l=l+1 ppn.gemiddelde.baksteen[j,3]=som/l ppn.gemiddelde.baksteen[j,2]=ppn ppn.gemiddelde.baksteen[j,1]=j} else{ ppn.gemiddelde.baksteen[j,3]=som/l ppn.gemiddelde.baksteen[j,2]=ppn ppn.gemiddelde.baksteen[j,1]=j ppn=baksteen.nu[i,2] j=j+1 som = baksteen.nu$creativiteitbaksteen[i] l=1 } } ppn.gemiddelde.baksteen<-ppn.gemiddelde.baksteen[-c(25,36),]
# blikje # blik
#analyse voor het maken van proefpersonen. Hierdoor zouden we kunnen kijken hoe verschillende personen dus hebben gescoord.
# eerste nemen we blik
blik.nu<-data.frame(blik$autresponse_id,blik$participant_fk, blik$ response,creativiteitblik) order.ppn.blik<-order(blik.nu$blik.participant_fk)
blik.nu<-blik.nu[order.ppn.blik,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.blik <- data.frame( nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.blik = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(blik.nu)){ if (blik.nu[i,2]==ppn){
som = som + blik.nu$creativiteitblik[i] l=l+1 ppn.gemiddelde.blik[j,3]=som/l ppn.gemiddelde.blik[j,2]=ppn ppn.gemiddelde.blik[j,1]=j} else{ ppn.gemiddelde.blik[j,3]=som/l ppn.gemiddelde.blik[j,2]=ppn ppn.gemiddelde.blik[j,1]=j ppn=blik.nu[i,2] j=j+1 som = blik.nu$creativiteitblik[i] l=1 } }
# boek
#analyse voor het maken van proefpersonen. Hierdoor zouden we kunnen kijken hoe verschillende personen dus hebben gescoord.
# eerste nemen we boek
boek.nu<-data.frame(boek$autresponse_id,boek$participant_fk, boek$ response,creativiteitboek) order.ppn.boek<-order(boek.nu$boek.participant_fk)
boek.nu<-boek.nu[order.ppn.boek,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.boek <- data.frame( nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.boek = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(boek.nu)){ if (boek.nu[i,2]==ppn){
som = som + boek.nu$creativiteitboek[i] l=l+1 ppn.gemiddelde.boek[j,3]=som/l ppn.gemiddelde.boek[j,2]=ppn ppn.gemiddelde.boek[j,1]=j} else{ ppn.gemiddelde.boek[j,3]=som/l ppn.gemiddelde.boek[j,2]=ppn ppn.gemiddelde.boek[j,1]=j ppn=boek.nu[i,2] j=j+1 som = boek.nu$creativiteitboek[i] l=1 } }
insertRow <- function(existingDF, newrow, r) {
existingDF }
nrow(ppn.gemiddelde.boek)
ppn.gemiddelde.boek<-insertRow(ppn.gemiddelde.boek,c(11,22,0),11) ppn.gemiddelde.boek<-ppn.gemiddelde.boek[-c(35,36,37),]
# eerste nemen we handdoek
handdoek.nu<-data.frame(handdoek$autresponse_id,handdoek$participant_fk, handdoek$ response,creativiteithanddoek)
order.ppn.handdoek<-order(handdoek.nu$handdoek.participant_fk) handdoek.nu<-handdoek.nu[order.ppn.handdoek,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.handdoek <- data.frame( nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.handdoek = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(handdoek.nu)){ if (handdoek.nu[i,2]==ppn){
som = som + handdoek.nu$creativiteithanddoek[i] l=l+1 ppn.gemiddelde.handdoek[j,3]=som/l ppn.gemiddelde.handdoek[j,2]=ppn ppn.gemiddelde.handdoek[j,1]=j} else{ ppn.gemiddelde.handdoek[j,3]=som/l ppn.gemiddelde.handdoek[j,2]=ppn ppn.gemiddelde.handdoek[j,1]=j ppn=handdoek.nu[i,2] j=j+1 som = handdoek.nu$creativiteithanddoek[i] l=1 }
ppn.gemiddelde.handdoek<-ppn.gemiddelde.handdoek[-c(19,36),] # paperclip paperclip.nu<-data.frame(paperclip$autresponse_id,paperclip$participant_fk, paperclip$ response,creativiteitpaperclip) order.ppn.paperclip<-order(paperclip.nu$paperclip.participant_fk) paperclip.nu<-paperclip.nu[order.ppn.paperclip,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.paperclip <- data.frame( nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.paperclip = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(paperclip.nu)){ if (paperclip.nu[i,2]==ppn){
som = som + paperclip.nu$creativiteitpaperclip[i] l=l+1 ppn.gemiddelde.paperclip[j,3]=som/l ppn.gemiddelde.paperclip[j,2]=ppn ppn.gemiddelde.paperclip[j,1]=j} else{ ppn.gemiddelde.paperclip[j,3]=som/l ppn.gemiddelde.paperclip[j,2]=ppn ppn.gemiddelde.paperclip[j,1]=j ppn=paperclip.nu[i,2] j=j+1 som = paperclip.nu$creativiteitpaperclip[i] l=1 } } ppn.gemiddelde.paperclip<-ppn.gemiddelde.paperclip[-c(35,36),] # riem
order.ppn.riem<-order(riem.nu$riem.participant_fk) riem.nu<-riem.nu[order.ppn.riem,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.riem <- data.frame( nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.riem = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(riem.nu)){ if (riem.nu[i,2]==ppn){
som = som + riem.nu$creativiteitriem[i] l=l+1 ppn.gemiddelde.riem[j,3]=som/l ppn.gemiddelde.riem[j,2]=ppn ppn.gemiddelde.riem[j,1]=j} else{ ppn.gemiddelde.riem[j,3]=som/l ppn.gemiddelde.riem[j,2]=ppn ppn.gemiddelde.riem[j,1]=j ppn=riem.nu[i,2] j=j+1 som = riem.nu$creativiteitriem[i] l=1 } } ppn.gemiddelde.riem<-ppn.gemiddelde.riem[-c(35,36),] # eerste nemen we stok
stok.nu<-data.frame(stok$autresponse_id,stok$participant_fk, stok$ response,creativiteitstok) order.ppn.stok<-order(stok.nu$stok.participant_fk)
stok.nu<-stok.nu[order.ppn.stok,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
nummer = numeric(36), proefpersoon= numeric(36), Gemiddelde.stok = numeric(36), stringsAsFactors=FALSE ) j=1 som=0 l=0 ppn=1 for (i in 1:nrow(stok.nu)){ if (stok.nu[i,2]==ppn){
som = som + stok.nu$creativiteitstok[i] l=l+1 ppn.gemiddelde.stok[j,3]=som/l ppn.gemiddelde.stok[j,2]=ppn ppn.gemiddelde.stok[j,1]=j} else{ ppn.gemiddelde.stok[j,3]=som/l ppn.gemiddelde.stok[j,2]=ppn ppn.gemiddelde.stok[j,1]=j ppn=stok.nu[i,2] j=j+1 som = stok.nu$creativiteitstok[i] l=1 } } ppn.gemiddelde.stok<-ppn.gemiddelde.stok[-c(35,36),] # vork
vork.nu<-data.frame(vork$autresponse_id,vork$participant_fk, vork$ response,creativiteitvork) order.ppn.vork<-order(vork.nu$vork.participant_fk)
vork.nu<-vork.nu[order.ppn.vork,]
# moet elk proefpersoon een gemiddelde creativiteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.gemiddelde.vork <- data.frame( nummer = numeric(36),
proefpersoon= numeric(36), Gemiddelde.vork = numeric(36), stringsAsFactors=FALSE
j=1 som=0 l=0 ppn=1 for (i in 1:nrow(vork.nu)){ if (vork.nu[i,2]==ppn){
som = som + vork.nu$creativiteitvork[i] l=l+1 ppn.gemiddelde.vork[j,3]=som/l ppn.gemiddelde.vork[j,2]=ppn ppn.gemiddelde.vork[j,1]=j} else{ ppn.gemiddelde.vork[j,3]=som/l ppn.gemiddelde.vork[j,2]=ppn ppn.gemiddelde.vork[j,1]=j ppn=vork.nu[i,2] j=j+1 som = vork.nu$creativiteitvork[i] l=1 } } ppn.gemiddelde.vork<-ppn.gemiddelde.vork[-c(25,36),] ppn.gemiddelde.alles<-data.frame(ppn.gemiddelde.baksteen,ppn.gemiddelde.blik[,3],ppn.gemiddelde.boek[,3],ppn.gemidd elde.handdoek[,3],ppn.gemiddelde.paperclip[,3],ppn.gemiddelde.riem[,3],ppn.gemiddelde.stok[,3], ppn.gemiddelde.vork[,3]) mean<-apply(ppn.gemiddelde.alles[,3:10],1,mean) ppn.gemiddelde.alles<-data.frame(ppn.gemiddelde.alles,mean)
# groepen maken van de proefpersonen hist(mean) group=numeric(34) group[(mean>0)&(mean<3.6)]=1 group[(mean>3.59)&(mean<4.0)]=2 group[(mean>3.99)&(mean<4.25)]=3 group[(mean>4.24)&(mean<4.5)]=4 group[(mean>4.48)]= 5
hist(group) group1<-subset(ppn.gemiddelde.alles,group==1) group2<-subset(ppn.gemiddelde.alles,group==2) group3<-subset(ppn.gemiddelde.alles,group==3) group4<-subset(ppn.gemiddelde.alles,group==4) group5<-subset(ppn.gemiddelde.alles,group==5)
# deze groepen vergelijken met elkaar
# --- # alles voor elke proefpersoon verschillend maken. # baksteen
# --- # alles voor elke proefpersoon verschillend maken. # baksteen
#analyse voor het maken van proefpersonen. Hierdoor zouden we kunnen kijken hoe verschillende personen dus hebben gescoord.
# eerste nemen we baksteen
baksteen.originaliteit<-data.frame(baksteen$autresponse_id,baksteen$participant_fk, baksteen$ response,originaliteitbaksteen)
order.ppn.baksteen<-order(baksteen.originaliteit$baksteen.participant_fk) baksteen.originaliteit<-baksteen.originaliteit[order.ppn.baksteen,]
# moet elk proefpersoon een gemiddelde originaliteit krijgen. # hier komt per proefpersoon het gemiddelde.
ppn.originaliteit.baksteen <- data.frame( nummer = numeric(36),
proefpersoon= numeric(36),
Gemiddelde.baksteen = numeric(36), stringsAsFactors=FALSE