Eindexamen wiskunde B1-2 havo 2004-I
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Vaas
19. De vaas wordt 16 – 4 cm = 12 cm breder in 21 cm, 20 @ 21
dus wordt hij 24 – 4 cm = 20 cm breder in –––––– cm = 35 cm 12
^ ^ (want 12 cm = 21 cm en 20 cm = x cm)
20. SF = (16 – 4) @ ½ = 6
en dus geldt AS = ½ @ (24 – 2 @ SF – FG) =
= ½ @ (24 – 12 – 4) = 4 p ADF = p ADS + p SDF
tan (p ADS) = 4/21 ! p ADS = 10,78 o tan (p SDF) = 6/21 ! p SDF = 15,95 o
! p ADF = 10,78 o + 15,95 o = 26,7 o
21. R = 2r ! 2r = -1
2r + 3 . 5000
30 - 3
4 r2
π .
159,155 – 3/4 @ r 2 = (2r + ½r) 2 = 6 1/4 r 2 ! r 2 = 1/7 @ 159,155 ! r = 4,768
! R = 2 @ 4,768 = 9,537 Dus er geldt dan r = 4,8 cm en R = 9,5 cm
