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Manipulation of ultracold Bose gases in a time-averaged orbiting potential - A: Quadrupole field with permanent magnets

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Manipulation of ultracold Bose gases in a time-averaged orbiting potential

Cleary, P.W.

Publication date

2012

Link to publication

Citation for published version (APA):

Cleary, P. W. (2012). Manipulation of ultracold Bose gases in a time-averaged orbiting

potential.

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Appendix A

Quadrupole field with permanent

magnets

A 2D quadrupole field can be produced by a simple geometry of just one pair of permanent magnets [50]. In this section the design of such a quadrupole field will be discussed. First we consider the magnetic field at position R = (R, θ, ϕ) relative to the position r0= (x0, y0, z0)of a single magnetic point dipole m of dipole moment

m =|m| pointing parallel to the y axis of a Cartesian plane as shown in Fig. A.1. The field B (r) at position r can be expressed as

Br= μ0

2m cos θ

4πR3 ; Bθ= μ0

m sin θ

4πR3 ; Bφ= 0, (A.1)

where cos θ = (y − y0) /r, sin θ =

1− cos2θwith 0 ≤ θ ≤ π and

R =|r − r0| =



(x− x0)2+ (y− y0)2+ (z− z0)2. (A.2)

Here x, y and z are the cartesian components of r. The Cartesian components of the field are given by

Bx(R, θ, ϕ) = Brsin θ cos φ + Bθcos θ cos φ (A.3a)

By(R, θ, ϕ) = Brcos θ− Bθsin θ (A.3b)

Bz(R, θ, ϕ) = Brsin θ sin φ + Bθcos θ sin φ, (A.3c)

where cos φ = (x − x0) /ρ and sin φ = (z − z0) /ρ, with ρ = R sin θ.

Substituting Eq. (A.1) into (A.3) the field components at position r = (x, y, z) created by a single point dipole become

Bx(x, y, z) = 3μ0m 4πR5 (x− x0) (y− y0) (A.4a) By(x, y, z) = 3μ0m 4πR5[(y− y0) 2 − r2/3] (A.4b) Bz(x, y, z) = 3μ0m 4πR5 (z− z0) (y− y0) . (A.4c)

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94 APPENDIX A. QUADRUPOLE FIELD WITH PERMANENT MAGNETS R Br Bș y x (x,y,z) (x0,y0,z0) r ș

Figure A.1: A single dipole m orientated parallel to the y-axis and the polar components Brand Bϑof the magnetic field at an arbitrary point (x,y,z).

Let us now turn to the field created by two identical point dipoles m1 and m2

positioned on the x axis at x1= x0 and x2=−x0, with m1 pointing in the positive

y direction and m2 pointing in the negative y direction as shown in Fig. 2.6. We

shall show that, close to the origin, these dipoles give rise to a quadrupole field in the x-y plane. The distances d1and d2 to dipoles m1 and m2 can be expressed as

d2

1 = (x− x0)2+ y2+ z2 and d22 = (x + x0)2+ y2+ z2, respectively. Substituting

y2= r2

− x2

− z2

and assuming |z| r x0 yields

Bx= Bx1+ Bx2 3μ0m 4π  1 d5 1 + 1 d5 2  x0y 3μ0m 4π 2y/x 4 0 (A.5a) By= By1+ By2 3μ0m 4π  1 3d3 1 −3d13 2  0m 4π 2x/x 4 0 (A.5b) Bz= Bz1+ Bz2 3μ0m 4π  1 d5 1 + 1 d5 2  yz 3μ0m 4π 10xyz/x 6 0 (A.5c)

Note that (close to the origin) the field has indeed the symmetry of the 2D quadrupole in the x-y plane, with the modulus of the field increasing linearly with the distance to the z axis.

Next we replace the point dipoles by homogeneously magnetized bar magnets of Neodymium Iron Boron. The magnetization M inside a bar is the magnetic moment per unit volume. As the bars are magnetized to saturation the magnetization is constant over the volume of the bar. Hence, the magnetic field is obtained by replacing mby M and integrating over the volume. Using Eq.(A.4) for a bar magnet of volume ΔxΔyΔzat position rn= (xn, yn, zn)with magnetization M pointing in the positive

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95 given by Bx(r, rn) = 3μ0 4πM  rmax(rn) rmin(rn) dx dy dz (x− x ) (y − y ) r5 (A.6a) By(r, rn) = 3μ0 4πM  rmax(rn) rmin(rn) dx dy dz [(y− y ) 2 − r2/3] r5 (A.6b) Bz(r, rn) = 3μ0 4πM  rmax(rn) rmin(rn) dx dy dz (z− z ) (y − y ) r5 . (A.6c)

where rmin= (xmin, ymin, zmin)and rmax = (xmax, ymax, zmax), with xmin= xn− Δx/2

and xmax = xn + Δx/2 and analogous expressions for ymin, ymax, zmin and zmax.

Evaluating the integrals the field components take the form

Bx(r, rn) =− μ0 4πM 1  i,j,k=0 (−1)i+j+karcsinh[ z− znk (x− xni) 2 + (y− ynj) 2] (A.7a) By(r, rn) = + μ0 4πM 1  i,j,k=0 (−1)i+j+karctan[ (x− xni) (z− znk) / (y− ynj) (x− xni)2+ (y− ynj)2+ (z− znk)2 ] (A.7b) Bz(r, rn) =− μ0 4πM 1  i,j,k=0 (−1)i+j+karcsinh[ x− xnk  (z− zni)2+ (y− ynj)2 ], (A.7c)

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