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The day the current disappeared

Johan.Rens@nwu.ac.za 3 May 2019

(2)

Contents

• Finding current: What did Maxwell miss?

• Why the Polish knight wanted to climb another

mountain…

• That is why the current went missing!

• Until sanity was restored by the IEEE 1459-2010

• Application in impedance-constrained networks

(3)

A brief history of nearly every electron

• Electricity as a matter of physics since BC

• Found application during 1800’s: “electrical engineering” – using this

resource to do “something”, mostly to better life for mankind

• Moving electrically charged electrons and protons = current is flowing

• Mostly done in an alternating manner (ac electricity)

• How well it is done governed by the constant law of misery in electrical

circuits: Ohm

(4)

On average, the voltage remains shockingly zero

i(t)

v(t)

source

v(t)

load

v(t)

loss

Resistive component of loadReactive component: L, C or both

-1.2 -1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 1.2 V ol ta ge time (ms) p(t) = v(t) * i(t)

= Vmax*Imax * cos(wt +d)cos(wt +b) = 1

2 2Vrms 2Irmscos(d -b)+ VrmsIrmscos(d -b)cos 2(

[

wt +d)

]

+ VrmsIrmssin(d -b)sin 2éë

(

wt +d

)

ùû = VRMSIRMScos

(

d -b

)

{

1+ cos 2éë

(

wt +d

)

ùû

}

+ VRMSIRMSsin

(

d - b

)

sin 2éë

(

wt +d

)

ùû

(5)

That is why that single-phase generator remained so small….

i(t)

v(t)

source

v(t)

load

v(t)

loss

(6)

v(t)

b

v(t)

c

v(t)

a

i(t)

a

i(t)

b

i(t)

c

p(t)

a

p(t)

c

p(t)

b

p(t)

3-phase

(7)

The War of Currents winner : George Westinghouse; 1886

v

a

(

t) = 2V

LN

cos(

w

t +

d

)

v

b

(

t) = 2V

LN

cos(

w

t +

d

- 120

0

)

v

a

(

t) = 2V

LN

cos(

w

t +

d

- 240

0

)

i

a

(

t) = 2I

L

cos(

w

t +

b

)

i

b

(

t) = 2I

L

cos(

w

t +

b

- 120

0

)

i

c

(

t) = 2I

L

cos(

w

t +

b

- 240

0

)

(8)

The War of Currents winner : George Westinghouse; 1886

p3j(t) = pa(t) + pb(t) + pc(t)

= 3VLNIL cos(

d

-

b

) + VLNIL cos(

d

-

b

) + VLNIL[cos(

d

-

b

) + VLNIL cos(2

w

t +

d

+

b

)+ ... ....+ cos(2

w

t +

d

+

b

- 2400)+ cos(

d

-

b

) + V

LNIL cos(2

w

t +

d

+

b

+ 240

0)] = 3VLNIL cos(

d

-

b

) = P3j

(9)

And if those voltages are no longer symmetrical and

those currents unbalanced?

The time-independent feature of three-phase energy transfer is

(10)

It get worse when the load is non-linear (and supply

voltage non-sinusoidal)….

• What does non-linear loading mean?

• More or less the modern way of consuming current

• Such as in a LED lamp, a laptop charger and and and

• Nowadays, MW’s and kV’s

• The energy transfer is impacted • We are used to:

Not anymore…. LED lamp Laptop charger

S= P + jQ

\ S

2

=P

2

+Q

2 2 2 2

S > P + Q

D

2

=S

2

- P

2

- Q

2

(11)

Now this is where the current got

lost!

• Distortion power?

• What is that?

• Something missing in power theory?

•Budeanu defined the concept of distortion power – as

“distortion” is the cause

• Many contributions to power theory followed

• Modern power phenomena required new definition

• Engineers have to design, specify and operate power system in

which energy phenomena has physical intrepetation

• Why is the term “distortion power” then still in use?

• Discussion became intense………

(12)

Sixth International Workshop on Power Definitions and Measurements under Non-Sinusoidal

(13)

And then the Polish knight arrived…

(14)
(15)
(16)

Shouldn’t we rather abandon the

knighthood?

(17)

But what is the problem?

• Steinmetz (1892): Ratio of active to apparent power decrease when waveform becomes more distorted such as electric arc (lighting application).

• Impact of distortion and unbalance new phenomena • Power factor reduction a concern

-• Unbalance in loading, asymmetry in supply voltages, AND distortion in voltage and/or current contributes to the degradation of power factor (the effiency in the

transfer of real energy)

• Classical power theory can only deal with perfectly sinusoidal voltages, perfectly

symmetrical between phases and perfectly linear loads that withdraw perfectly balanced currents

• Budeanu (1927) described S2 > P2+Q2 when waveforms are non-sinusoidal

 IEEE-1459-2010 attempted to further practical formulations universally acceptable for engineers to deal with modern power systems

(18)
(19)

Effective values: nonsinusoidal waveform conditions (1)

• A non-sinusoidal, single-phase, time-dependent voltage v(t)with fixed and repetitive period

T is applied to a load - represented as a finite series of harmonic components: h=1, 5, 7

• Single phase distortion component of v(t) can be isolated as vH(t):

• The IEEE 1459-2000 document further practical guidelines on power definitions •The time-domain or the frequency domain can be used for power definitions • Focus will be on frequency domain power definitions in this presentation

( )

1

( )

1

(

1

)

(

5

)

(

7

)

1

1 1

1sin sin 5 sin 7

5 7 N h h v t v t

w 

t

w 

t

w 

t = =

v

H

( )

t

= - + - + -1

=

2

V

h

sin(

hwt+ a

h

)

h¹1 N

=

1

5

sin 5

(

wt-

5

)

+

1

7

sin 7wt-

(

7

)

(20)

Effective values: nonsinusoidal waveform conditions (2)

• i(t) when v(t) is applied to frequency dependent impedance load: • Distortion components i

( )

H(t)

( )

:

(

)

[

]

,1 1 1 1 1 1 2 sin 1,5,7 N N h h h h h i t i t I h t h   

w

b

= = = = + =

( )

1 1 1

2 sin(

)

N H h h h

i t

I

h t

w

b

¹

=

+

(21)

Active Power: nonsinusoidal waveform conditions

• The effective or RMS values: • The single phase power:

• Classical power theory formulates Time-dependent Active Power (per harmonic order h):

• The Time-dependent Total Active Power of a circuit under distorted waveform conditions:

• Total (or Joint) Average Active Power requires integration over a period T:

2 2 1 ,1 1 ,1 1 1 ; N N h h h h V I = = =

V =

I

( ) ( )

( )

( )

1 1 1 1 1 1 1

( )

N h N h h h

p t

v t

i t

v t

i t

= =



=

= 





( )

1

Re 2

( )

1

Re 2

( )

1 h h h

p t

=

ë

é

v

t

ù

û

ë

é

i

t

ù

û

( )

1

( )

1 1 N h h p t p t = =

( )

(

)

1 1 ,1 ,1 1 1 cos N h h h h h T P p t dt V I T   a b = =

=

(22)

-Reactive Power: nonsinusoidal waveform conditions

• Classical power theory formulates Time-dependent Reactive Power (per harmonic order h):

• The Time-dependent Total Reactive Power of a circuit under distorted waveform conditions:

• Total (or Joint) Average Reactive Power requires integration over a period T: Does it make sense?

It does not make sense!

q t

( )

h

= Re 2v t

é

ë

( )

h

ù

û Im 2i t

é

ë

( )

h

ù

û

( )

( )

1 N h h q t q t = =

QB = 1 T T

q t

( )

= 1 T q t

( )

h h=1 N

= T

Vh,1Ih,1 sin

(

a

h -

b

h

)

h=1 ¥

(23)

Summary of Budeanu’s definitions

Total Active Power Total Reactive Power (Budeanu’s Reactive Power) Budeanu’s Distortion Power

( ) ( )

( )

( )

1 1 1 1 1 1 1

( )

N N h h h h

p t

v t

i t

v t

i t

  = =

=

=

( )

1 ,1

(

1

)

,1

(

1

)

1 1 2 2 2 ,1 ,1 ,1 1 1 , 1( )

2

sin

*

2

sin

N N h h h h h h N N N h B h k h h h k h k H B B

p t

V

h t

I

h t

P

Q

P

Q

D

     

w

a

w

b

= = = = = ¹

=

+

+

=

+

+ 

=

+

+

V

I

(24)

What is wrong with Q

B

– the Budeanu Reactive Power?

• Physical nature of reactive power follows from the application of field theory (Maxwell’s equations)

• Reactive Power not to contribute to real energy transfer

• Physical nature of reactive power - energy accumulation in electric and magnetic fields of reactive components in the load and source

• Results in oscillatory exchange of energy between these reactive components

• Similar explanation assigned to harmonic reactive power Qh at each harmonic order h

• Is QB (Joint/Total Reactive Power) a useful concept? • Let’s investigate……

( )

( )

,1 ,1

(

)

1 1 1 1 sin N B h h h h h h h T T Q q t q t V I T T   a b ¥ = = =

=

=

(25)

-Application of Q

B

in power factor correction (1)

v(t) 10 ohm 100 mH i(t) • PF = 0.3 based on QB

v t

( )

1

=

100

h

sin 2

(

×π × 50 × h×t

)

;

hÎ 1,5,7,11

[

]

(26)

Application of Q

B

in power factor correction (2)

v(t) 10 ohm

100 mH

64 μF

i(t)

• Calculate the capacitance in parallel to compensate QB

2 2 2 2 1 1 5 5 7 7 11 11 B

Q

C

V

w

V

w

V

w

V

w

=

+

+

+

(27)

Application of Q

B

in power factor correction (3)

• QB completely compensated by capacitor, but- power factor of compensated circuit did not change significantly.

• Apparent power is less in compensated circuit but unnecessary loading remains (difference between apparent power and real power).

Remark

• Budeanu’s reactive power (QB) not useful for power factor compensation.

• Power factor correction results in “distortion power” (DB) to increase significantly due to increased interaction between uneven harmonic voltage and current components.

(28)

Does distortion power D

B

make sense?

v(t) 1 ohm i(t) Time V ol ta ge 1.676 1.676 -Vac j 600 0 j Time C ur re nt 1.676 1.676 -Iac j 600 0 j

• DB has zero value: waveforms perfectly sinusoidal? • Both voltage and current are distorted!

• DB does not relate to degree of waveform distortion.

v t

( )

1

=

1

(29)

Summary: Power theory in a modern

power system

• It must, as far as possible consist of a generalisation of the classic single-frequency power theory that has by now been universally accepted.

• It must be as amenable to conventional measurement techniques as possible and require the minimum of sophistication in instrumentation.

• It’s different defined components must be relatable to physically observable or ascribable phenomena and not to hypothetical or abstract mathematical

definition.

• It must present a suitable basis for quantifiable measurement, control, tariff systems and design.

• It must cater for every conceivable practical situation and never violate circuit laws, regardless of which domain it is transformed into.

• It must be useful to the engineer who has to apply these definitions in design, specification and operation of the power system.

(30)

LPQI is part of

LPQI-VES is co-financed by

2. The IEEE 1459 made easy

(31)

What is a modern Power System? (1)

-400 -300 -200 -100 0 100 200 300

400 Line-neutral voltages in a 400 V power system

P h a s e V o lt a g e s ( V )

(32)

What is a modern Power System? (2)

-80 -60 -40 -20 0 20 40 60 80

Three phase line-currents in a 400 V power system

P h a s e c u rr e n ts ( A )

(33)

What is a modern Power System? (3)

Condition 3: Unbalance in loading…

-1000 -800 -600 -400 -200 0 200 400 600 800

1000 Load Currents withdrawn by Arc Furnace

C u rr e n t (A )

(34)

What is a modern Power System? (3)

-60000 -40000 -20000 0 20000 40000 60000

Asymmetrical voltages at PCC feeding Arc Furnace

L in e -L in e V o lt a g e s (V )

(35)

The IEEE 1459-2000: Voltage and Current (1)

• A Three-phase power system under non-sinusoidal waveform conditions, unbalanced loading and asymmetrical supply voltages is considered.

• Sinusoidal, balanced and single-phase power system operation is easily introduced as a simplification

Define nonsinusoidal line-neutral voltages and line currents:

, , 0 0 , , 0 0 , , 0 ( ) 2 sin( ) ( ) 2 sin( 120 ) ( ) 2 sin( 120 ) a a h a h h b b h a h h c c h c h h v t V h t v t V h t h v t V h t h w a w a w a ¥ ¹ ¥ ¹ ¥ ¹ = + = + -= + +

0 , , 0 0 0 , , 0 0 0 , , 0 ( ) 2 sin( ) ( ) 2 sin( 120 ) ( ) 2 sin( 120 ) a a a h a h h b b b h a h h c c c h c h h i t I I h t i t I I h t h i t I I h t h

w

b

w

b

w

b

¥ ¹ ¥ ¹ ¥ ¹ = + + = + + -= + + +

(36)

The IEEE 1459-2000: Voltage and Current (2)

• DC components in voltage, (Va0, Vb0 and Vc0) should always be zero.

• DC values in line currents (Ia0, Ib0 and Ic0) could be nonzero depending on nature of load.

• The RMS line-neutral voltage Va and RMS line current Ia (similarly for phase b and c) are related to harmonic components by:

• Fundamental frequency and the nonfundamental frequency (harmonic frequencies grouped) 2 2 2 2 2 2 2 ,1 , ,1 , 2 2 2 2 2 2 2 2 2 ,1 , ,1 , 2 2

(

)

(

)

a a a h a aH aH a h h h a a a h a aH aH a h h h

V

V

V

V

V

V

V

I

I

I

I

I

I

I

¥ ¥ ¹ ¹ ¥ ¥ ¹ ¹

=

+

=

+

=

=

+

=

+

=

(37)

The IEEE 1459-2000: Voltage and Current (4)

What is the “effect” of three-phase voltages and three-phase currents in terms of the three-phase power system?

“Effective” voltage and “effective” current to represent the state of the

three-phase power system:

“Effective” voltage and “effective” current in a 3-wire three-phase power system:

2 2 2 1 2 2 2 1 e e eH e e eH

V

V

V

I

I

I

=

+

=

+

2 2 2 2 2 2

3

3

a b c e a b c e

V

V

V

V

I

I

I

I

+

+

=

+

+

=

(38)

Calculating the effective voltage and current (1)

If an artificial neutral point in a 3-wire three-phase system is not used to find the line-neutral voltage values, the effective three-phase voltage can be

calculated from the RMS phase-phase voltage values as:

• The fundamental frequency

componens of the effective voltage

and current in a 3-wire three-phase

power system: 2 2 2

9

ab bc ca e

V

V

V

V

=

+

+

2 2 2 ,1 ,1 ,1 ,1 2 2 2 ,1 ,1 ,1 ,1

9

3

ab bc ca e a b c e

V

V

V

V

I

I

I

I

+

+

=

+

+

=

(39)

Calculating the effective voltage and current (2)

• Non-fundamental frequency components of the effective voltage and current in a 3-wire three-phase power system:

• Non-fundamental frequency components relates to the harmonic components (line-neutral voltages assumed):

2 2 2 2 2 2

9

3

abH bcH caH eH aH bH cH eH

V

V

V

V

I

I

I

I

+

+

=

+

+

=

(

)

(

)

2 2 2 , , , 1 2 2 2 , , , 1

3

3

a h b h c h h eH a h b h c h h eH

V

V

V

V

I

I

I

I

¥ ¹ ¥ ¹

+

+

=

+

+

=

(40)

Calculating the effective voltage and current (3)

• Unbalanced condition in a

4-wire three-phase power system

requries reformulation of the

effective voltage and current :

• The fundamental

frequency components of

the effective voltage and

current in a 4-wire

three-phase power system:

(

2 2 2

)

2 2 2 2 2 2 2

1

3

18

3

e a b c ab bc ca a b c n e

V

V

V

V

V

V

V

I

I

I

I

I

é

ù

=

ë

+

+

+

+

+

û

+

+

+

=

(

2 2 2

)

2 2 2 ,1 ,1 ,1 ,1 ,1 ,1 ,1 2 2 2 2 ,1 ,1 ,1 ,1 ,1

1

3

18

3

e a b c ab bc ca a b c n e

V

V

V

V

V

V

V

I

I

I

I

I

é

ù

=

ë

+

+

+

+

+

û

+

+

+

=

(41)

Calculating the effective voltage and current (4)

• The non-fundamental frequency components of the effective voltage and

current in a 4-wire

three-phase power system:

Implementation straightforward with modern digital instrumentation

(

2 2 2

)

2 2 2 2 2 2 2

1

3

18

3

eH aH bH cH abH bcH caH aH bH cH nH eH

V

V

V

V

V

V

V

I

I

I

I

I

é

ù

=

ë

+

+

+

+

+

û

+

+

+

=

(42)

And power? Not all S is the same S…..

• Arithmetic apparent power SA:

• Active, Budeanu’s reactive and

distortion power is summated over all three phases:

• Vector apparent power Sv:

• The Budeanu power definition for single-phase power systems are applied per phase 2 2 2 2 2 2 2 2 2 a a Ba Ba b b Bb Bb c c Bc Bc A a b c

S

P

Q

D

S

P

Q

D

S

P

Q

D

S

S

S

S

=

+

+

=

+

+

=

+

+

=

+

+

,3 a b c B Ba Bb Bc B Ba Bb Bc

P

P

P

P

Q

Q

Q

Q

D

D

D

D

 

=

+

+

=

+

+

=

+

+

2 2 2 ,3 V B B S = P + Q + D

(43)

And the effective apparent power

is…..

The three-phase or system effective apparent power Se can be written in terms of the contribution of all harmonic components:

The components in the system effective apparent power Se can be grouped in the

fundamental and nonfundamental frequency voltage and current components:

The non-fundamental frequency apparent power SeN consist of 3 “distortion” components:

S

e2

= (V

e

I

e

)

2

= (V

e,1

I

e,1

)

2

+ (V

e,1

I

eH

)

2

+ (V

eH

I

e,1

)

2

+ (V

eH

I

eH

)

2 2 2 2 ,1 e e eN

S

=

S

+

S

S

eN2

= V

e,1

I

eH

(

)

2

+ V

(

eH

I

e,1

)

2

+ V

(

eH

I

eH

)

2

= D

eI2

+ D

eV 2

+ D

eH 2

(44)

And the “distortion” powers are…..

Ve,1IeH: The current distortion power, DeI

VeHIe,1: The voltage distortion power, DeV

VeHIeH: The harmonic distortion power, DeH

An effective harmonic apparent power SeH is defined:

2 2 2 ,3 eH H eH

S

=

P

+

D

(

) (

2

)

2

(

)

2 2 ,1 ,1 2 2 2 eN e eH eH e eH eH eI eV eH

S

V I

V I

V I

D

D

D

=

+

+

=

+

+

(45)

The Total Three-Phase Active Power

The Joint (Total) Harmonic Active Power of three-phase power system:

The Joint Active Power of three-phase power system:

(

)

3 1 3 1 Re N H , ah ah bh bh ch ch h N h, h P P      ¹ ¹ = + + =

V I V I V I

( )

( )

(

)

3 3 3 1 3 1 Re N ah ah bh bh ch ch h N h, h P t t P     = = é ù = ë û = + + =

v ,i V I V I V I

(46)

And how much is that “distortion”?

Quantification on the level of distortion is done with three-phase effective values:

Voltage total harmonic distortion factor: VTHDe

Current total harmonic distortion factor: ITHDe

The IEEE 1459-2000 write these symbols as THDeV and THDeI

,1 , ,1 eH e e e H e e

V

VTHD

V

I

ITHD

I

=

=

(47)

These distortion factors are useful!

A shortcut to SeN:

And to DeI; DeV; DeH (The “distortion” powers):

To do what with?

(

)

2 1 eN e e e e e

S

=

S VTHD

+

ITHD

+

VTHD ITHD

1 1 1 eI e e eV e e eH e e e

D

S ITHD

D

S VTHD

D

S ITHD VTHD

=

=

=

(48)

To quantify the pollution….

Harmonic pollution (SeN/Se1):

Unbalance pollution:

The positive sequence voltage (V1+) and current (I

1+) in the

three-phase fundamental frequency components have to be found…..

Then calculate:

The “unbalance pollution”:

“Unbalance pollution” includes both the effect on loading unbalance and voltage asymmetry

S

eN

S

e1





2

= ITHD

(

e

)

2

+ VTHD

(

e

)

2

+ ITHD

(

e

VTHD

e

)

2

S

1 +

= 3V

1 +

I

1 +

S

u1

= S

e12

- S

1 +

( )

2

UnbalancePollution(%) =

S

u1

S

e1

*100

(49)

What powers are “useful”?

The positive sequence components in the three-phase fundamental frequency voltages and currents:

The 50 Hz positive sequence active power:

The 50 Hz positive sequence reactive power:

The 50 Hz positive sequence apparent power: And power factor?

Various options exist….

Different answers to the same question!

P

1+

= 3V

1+

I

1+

cos

1+

Q

1 +

= 3V

1 +

I

1 +

sin

1 + S1+

( )

2 = P

( )

1+ 2 + Q 1 +

( )

2

(50)

Power factor formulations

Different apparent powers have been formulated: • Arithmetic apparent power, SA

• Vector apparent power, Sv

• Three-phase effective apparent power, Se • Positive sequence apparent power, S1+

Different apparent power factors have been formulated:

• Arithmetic apparent power factor • Vector apparent power factor

• Three-phase effective apparent power factor

• Positive sequence apparent power factor 1 1 P PF S + + + = A A P PF S = V V P PF S = PFe = P,3 Se = P1,3 + PH ,3 Se

(51)

Which power factor should be used?

If the waveforms are sinusoidal, the loading in perfect balance and the supply voltages in perfect symmetry, then:

In a practical power system with distorted waveforms, unbalanced loading and asymmetrical supply voltages:

• PFe reflects the impact of harmonics and asymmetrical waveforms the best.

The smallest numerical value – regulatory application

What power factor formulation does your instrument use?

A V e

PF = PF = PF = PF+

e A V

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3. Case Study

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Application of IEEE 1459-2000 - practical power system

Rs + ωLs 6-pulse controller Heating load RL + ωLL 11kV/400 V 1 MVA 0.01+j0.043 p.e. V and I measurements PCC

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Voltage and Current waveforms

-400 -300 -200 -100 0 100 200 300 400 Va Vb Vc Line-neutral voltages V o lt ag e ( V ) -800 -600 -400 -200 0 200 400 600 800 Ia Ib Ic Line currents C u rr e n t (A ) • Line-neutral voltages • Line Currents

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Waveform analysis: Fourier transform

The IEEE 1459 power definitions require translating time-domain waveforms to the frequency domain by means of the Fourier transform:

The level of distortion requires quantification: • ITHDe= 48.3%

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Isolating the distortion components

• The non-fundamental frequency components of the effective voltage and

current:

• The fundamental

frequency components of

the effective voltage and

current:

(

2 2 2

)

2 2 2 2 2 2 2

1

3

18

17.2 V

3

145.8 A

eH aH bH cH abH bcH caH aH bH cH nH eH

V

V

V

V

V

V

V

I

I

I

I

I

é

ù

=

ë

+

+

+

+

+

û

=

+

+

+

=

=

(

2 2 2

)

2 2 2 ,1 ,1 ,1 ,1 ,1 ,1 ,1 2 2 2 2 ,1 ,1 ,1 ,1 ,1

1

3

18

227.6 V

3

301.5 A

e a b c ab bc ca a b c n e

V

V

V

V

V

V

V

I

I

I

I

I

é

ù

=

ë

+

+

+

+

+

û

=

+

+

+

=

=

(57)

The three-phase effective voltage and current

The effective voltage and current :

The RMS line-neutral voltages per phase:

The RMS line currents per phase:

The RMS neutral current:

=

21

+

2

= 228.3 V

2

=

1 2

+

2

= 335 A

2 , 1 229.2 V 227.7 V 227.8 V a a h h b c V V V V ¥ = = = = =

2 , 1 315.4 A 342.9 A 345.8 A 8.1 A a a h h b c n I I I I I ¥ = = = = = =

(58)

The powers

Current distortion power: Voltage distortion power: Harmonic distortion power:

Effective apparent power: Arithmetic apparent power: Vector apparent power:

Joint (three-phase) active power: Joint harmonic active power:

1

7.5 kVar

eH e e e

D

=

S ITHD VTHD

=

199.7 KVA

V

S

=

(

)

3 3 1 1 Re N N 387 W H , ah ah bh bh ch ch h, h h P    P ¹ ¹ =

V I +V I +V I =

=

-( )

( )

(

)

3 3 3 3 1 1 Re N ah ah bh bh ch ch N h, 92 9 kW h h P t t    P . = = é ù = ëv ,i û =

V I +V I +V I =

= 1 229.4 KVA e S = 199.7 KVA A S = 1

99.9 kVar

eI e e

D

=

S ITHD

=

1

15.5 kVar

eV e e

D

=

S VTHD

=

(59)

And the power factors….

The arithmetic power factor: 0.465 p.u. The vector power factor: 0.465 p.u. The effective power factor: 0.405 p.u

And the “pollution” factors….

Harmonic pollution: Unbalance pollution: Unbalance factors:

( )

(

) (

2

) (

2

)

2 1 % *100 3.6% eN e e e e e S ITHD VTHD ITHD VTHD S = + + =

( )

2 2 1 1 1 1 1 9.1 KVA (%) *100 4.4% u e u e S S S S UnbalancePollution S + = - = \ = = 2 1 2 1 0.4% 3% UB UB V V V I I I = = = =

(60)

Summary

The three-phase effective power factor is numerically the smallest if unbalance and/or waveform distortion exist.

The contribution to apparent power by both voltage asymmetry and unbalance in loading, was shown to be significant even with “low” values in VUB and IUB.

The three-phase effective distortion index for voltage (VTHDe) and current (ITHDe) furthers straightforward calculation of distortion powers.

It is possible to isolate the contribution of harmonics to useles power by means of voltage distortion power (DV), current distortion power (DI) and harmonic distortion power (DH).

It is a helpful reflection on the impact of nonsinusoidal waveforms,

unbalanced loading and asymmetrical supply voltages from the point of view from operating such power system.

(61)

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Conclusion on Power Theory

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Conclusion

• The classical power theory explains phenomena in a power system with a sound physical explanation but is inadequate when waveforms are non-sinusoidal,

loading is unbalanced and voltage waveforms are asymmetrical.

Conform to Electrical Network Laws

• Numerous approaches to power theory exists which are formulated in either the time- or frequency domain.

• New contributions are forthcoming as inadequacies are better understood. • In general, a power theory has to:

Explain Physical Phenomena

Be Measurable

Enables Compensation

Referenties

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