Solution to Problem 65-7*: Solution to an integral equation
Citation for published version (APA):
Bouwkamp, C. J. (1966). Solution to Problem 65-7*: Solution to an integral equation. SIAM Review, 8(3), 393-395. https://doi.org/10.1137/1008085
DOI:
10.1137/1008085
Document status and date: Published: 01/01/1966
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PROBLEMS AND SOLUTIONS 393 Problem 65-6,
A
Ratioof
Two
Definite
Multiple Integrals,* byA. J. STRECOK
(Argonne NationalLaboratory). Determine
where
I(--1, x)/I(1, x),
I(s,
x)=
f0
f0
t(x2
t2)-l/2eS(t-u)
dudtfornonzeros andx.
Solutionby
P. J. SHORT
(White Sands MissileRange).The solution herecanbe obtained fromthesolution to Problem 64-8
(October,
1965).
Denotingthe integralinProblem 64-8 byI*(x),
itfollowsby making the substitutionsv u/
and w/
thatWhence,
%/7
I*
(x%/)
rI(s,x)
=---4s
1}.
Also solved by
R.
D. ADAMS (University ofKansas),
D. BEIN (Fairleigh DickinsonUniversity),C.
J.
BOtWKAMe (Technological University,Eindhoven, Netherlands), M.P. FRIEDMAN
(Smithsonian Institute), D. L. LANSING(NASA-Langley Research
Center), C.
B.A.
PECK(two
solutions) (PennsylvaniaState
College), H. B. ]OSENSTOCK
(U. S.
Naval Research Laboratory), L.RUBEN-FELD
(Courant
Institute of Mathematical Sciences),P. A.
SCHEINOK
(Hahne-mann Medical College),
C.
B.SHAW,
JR.
(Electro-OpticalSystems, Inc.), S.
SPITAL (CaliforniaState
Polytechnic College),F.
W.
STEUTEL
(Technische HogeschoolTwente,
Enschede,Netherlands)
andthe proposer.Problem
65-7",
Solution to an Integral Equation, byA. J. STRECOK
(Argonne NationalLaboratory).Show thatasolution oftheequation
1 e-x"
-
2te-t(x,
t)
dt isgiven by(2)
(x, t)
2(x2
t2)_1/2
f0
eu du,and give conditions on
(x, t)
whichmake this aunique solution.*Workperformedunder the auspices of the UnitedStatesAtomicEnergyCommission. Workperformedunderthe auspices oftheUnitedStatesAtomicEnergyCommission.
394 PROBLEMS AND SOLUTIONS
Solutionby
C. J.
BOUWKAMP (Technological University, Eindhoven,Nether-lands).
Thefirstpartoftheproblemis simpleinview of the solution given of Problem 65-6ifapplied tos -1, viz.,
2te-t(x,
t)
dt 4I(-1,
x)
1e-,
x>
O. The second partofthe problemis not wellposed. Equation(1)
isnot aproper integral equation. The functional equation(1)
has an abundance ofsolutions,
and conditions on
b(x, t)
that will make the particular solution(2)
the only solution of(1)
seem to be quite artificial. This is substantiated by noting it is easy to constructsolutions ofthe typesf(t)g(x) andf(t)
+
g(x),
wheref(t)
is wholly arbitrary.Thus,
1(X,
t)
f(t)(1
e-)
2te-tf(t)
dtand
.(x,
t)
1H-f(t)
(1
-e-)
-1f0
2te-tf(t)
dtare solutions of
(1)
for anyf(t)
making the right-hand side meaningful.Ap-parently,
the proposer is interested in solutions thataresingularat x t.How-ever, there is awhole class of such solutions. This isshown as follows.
Assume
that(1)
ismeant to hold forx>
0, and that#(x, t)
is defined and continuousfor0=_<
x.It
issomewhateasierto discusstheproblemin trans-formed variables.To
that end,setX
Then
(1)
becomesr,
x(,r) =h(x,t).
(3)
1 e-
"F
e-x(,
r)
dr,and the function
(2)
correspondsto(4)
X(,
r)
_1
(
r)
-/e’u
-lld,
this being aparticular sluion of
(a). In
fae, by invoking the theory ofAbel’s integral equation, his can beproved independently of the solution to Problem 65-6.Now
assumeha,)
whereg(t) isanunknownfunction and 0
<
a<
1.Then(4)
transformsintothe generalized Abel equation:PROBLEMS AND SOLUTIONS 395
whichissolved by
g(r)
e-
sin(ar)
e’u
"-
du. Thatisto say, in terms ofthe originalvariables, thefunction(5)
b(x,
t)
r(x.
_2
sin(or)t)
fo
e’u"-
duis aparticularsolution of
(1)
foranyawith0<
a<
1.Theproposer’s
solution(2)
is obtained for a1/2.
Of course, thereexist stillother solutions of
(1).
Thus, if the proposerwrites his unknown functionk(x, t)
as a product of the kernel function(x
and an unknown function
h(t),
the solution indicated forh(t)
is unique, by invoking the existing theory of Abel’s integral equation.But
then the kernel function should have been prescribed.Alsosolved by