Wind Energy, Part 2
Technical University of Eindhoven December 6, 2018 Gerard Schepers
ECN part of Tno/Hanze UAS Groningen
Gerard.schepers@tno.nl. +31 613100940
Contents
•
Principles of energy extraction, Betz-Lanchester
optimum
•
Design loads
•
Technology, state of the art
•
Wind Farm effects
•
Operation and Maintenance for Off-shore farms
What is a wind turbine:
A wind turbine transforms kinetic energy from the wind into mechanical (kinetic….) energy of the rotor(shaft)
Wind turbine Transformer Grid Pm = TΩ P e = V I cosf Wind V(x,y,z,t) Ekin = ½ rV2 Pkin= ½ rV3A Ekin = ½ rV2 Pkin= ½ rV3A 3
4 5-2-2019 Figure: Modified from F. Grasso(ECN)
The axial force from the rotor on the air is a result of the
lift on the blade
Optimum energy extraction
•
Lanchester, Betz and Joukowsky showed
independently (1916-1920) that optimum power
extraction is obtained when the wind speed at the
rotor disk is decelerated to 2/3 of its initial value
•
The relative reduction in wind speed at the rotor
plane is called the
axial induction factor a.
So, an axial induction factor of 1/3 leads to optimal
power production
•
Then power extracted = 16/27 (~0.59) of free wind
power (=1/2 ρ V
w3A
R
)
•
This is known as the Betz maximum
6 5-2-2019
• The velocity in the rotor plane is reduced with the induced velocity
The induced velocity is V
w– V
rotorVw
Vrotor
7 5-2-2019
• The velocity in the rotor plane is reduced with the induced velocity
• Kinetic energy is extracted from the flow lower velocity in the rotor plane
The induced velocity is V
w– V
rotorVw
Vrotor
8 5-2-2019
• The velocity in the rotor plane is reduced with the induced velocity
• Kinetic energy is extracted from the flow lower velocity in the rotor plane
• The axial force from the rotor on the air ‘brakes’’ down the airflow lower velocity in the rotor plane
The induced velocity is V
w– V
rotorVw
Vrotor
9 5-2-2019
• The velocity in the rotor plane is reduced with the induced velocity
• Kinetic energy is extracted from the flow lower velocity in the rotor plane
• The axial force from the rotor on the air ‘brakes’’ down the airflow lower velocity in the rotor plane
• The induced velocity can be related to the power/energy
(conservation of energy) and to the axial force(conservation of momentum)
The induced velocity is V
w– V
rotorVw
Vrotor
10 5-2-2019
• The velocity in the rotor plane is reduced with the induced velocity
• Kinetic energy is extracted from the flow lower velocity in the rotor plane
• The axial force from the rotor on the air ‘brakes’’ down the airflow lower velocity in the rotor plane
• The induced velocity can be related to the power/energy
(conservation of energy) and to the axial force(conservation of momentum)
• Together with P = Fax.Vrotorand conservation of mass the induced velocity is solved
The induced velocity is V
w– V
rotorVw
Vrotor
The induced velocity is made non-dimensional:
The axial induction factor a
Vw
a is the relative induced velocity
Vrotor w induced w rotor w
V
u
V
V
V
a
Vwake•
Power (energy/time) extracted from fluid:
– Scalar product of (negative) force vector on the flow and the velocity of the flow
•
However the main direction is axial so it is mainly the axial force
from the rotor on the flow (F
ax (or Dax or T from Thrust)) and the
axial velocity component U
d( where index d denotes disc value)
P
extracted= - F
axU
d•
The energy extraction from the rotor out of the flow will now
be approximated by assuming the rotor to be an actuator disk.
12
Fax
What is an actuator disc?
•An actuator disc is not ‘something real’ • It is a kind of porous disc, only
used to understand the process of the energy extraction
• Exerts axial force on air flow • Extracts power from flow
Constant pressure jump p over actuator disc
represents axial rotor force Fax : p = Fax / AR with AR the rotor area (=pR2)
In general rotor theory:
The rotor is represented as an actuator disc
R
L. Lignaroli,
On the turbulent mixing in horizontal axis turbine wakes TUDelft, April 2016
Turbine
‘Actuator disc’
Momentum theory
Flow geometry: Sections 1, 4: far upstream resp. downstream
Sections 2, 3: just upstream resp downstream of actuator disk
A1 A4
Stream tube boundary
U1 = Vw U4 AR U2=U3=Ud Fax Control volume A1 Actuator disc Sections: 1 2 3 4
Consider conservation laws on stream tube which contains actuator disc with axial force Fax in uniform flow
Flow assumptions
• Homogeneous, incompressible and inviscid fluid
• Steady state flow
• Actuator disk is semi-transparent to flow: creates pressure discontinuity
• Uniform flow conditions over disk.
Axial force Fax = (p2 - p3)AR Power extracted: Pextracted = Ud (p2 - p3)AR
Fluid dynamic conservation laws applied to stream
tube
1. Conservation of mass (per second through the streamtube)
2. Conservation of momentum 3. Conservation of energy m A U A U A U UA
r
1 1 r
d R r
4 4 r
U U
Fax m U m U m 1 4 1 4
U U
U U
FaxUd m 4 1 4 1 2 d axU F P U U m U m U m ) ( 2 2 2 2 4 2 1 2 4 2 1 Velocity in rotorplane (U
d) is mean of free stream
velocity (U
1) and the wake velocity (U
4)
Conservation of momentum Conservation of energy
U
U
F
axm
1
4
2 4 1 U U Ud
U
U
U
U
F
axU
dm
4 1 4 12
Express F
axand P in axial induction factor a
Define induced velocity (axial component) ui and write U1 = Vw Ud = U1 - ui= Vw - ui Define axial induction factor a:
Then: w i w i
u
aV
V
u
a
;
R w w
R w R w w R w w w R w ax R w R d w w w w w w w w w d w w w d A a a ρV a aV A a V U U m P A a a V a V A a V a V V A a V U U m F A a V A U m a aV a a V a a V V a V V U U a V V a V U U U a V aV V u U U 2 3 2 2 4 2 1 2 4 1 2 2 2 2 2 2 2 2 2 2 4 2 1 1 4 1 1 1 2 ) 1 ( 4 1 2 ) ( 2 1 2 2 ) 1 ( ] 2 1 [ ) 1 ( ] [ 1 ) 1 ( 4 ) 4 4 ( ) 4 4 1 ( 2 1 2 1 ) 1 ( 2 2 1 r r r r r r Next define an Axial force Coefficient and Power Coefficient
Axial force Coefficient (C
D,axor C
T) and
Power Coefficient (C
P):
2 3 2 1 2 3 3 2 1 2 2 1 2 2 2 1 ) 1 ( 4 1 2 ) 1 ( 4 1 2 a a A V A a a V A V P C a a A V A a a V A V F C R w R w R w P R w R w R w ax Dax r r r r r rThe axial force coefficient and the power coefficient
of an actuator disc are a function of a only
From conservation laws:
Maximum Cp found by differentiating with respect to
a:
2 1 4 1 4 a a C a a C P Dax
13 2 2 2 2 20
3
1
1
0
3
4
1
0
2
2
2
1
0
1
2
1
0
1
8
1
4
0
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
da
dC
PThe maximum value of C
PValues of C
Pand C
Tat maximum energy
extraction condition:
9
8
)
3
1
1
(
3
1
4
)
1
(
4
5926
.
0
27
16
)
3
1
1
(
3
1
4
)
1
(
4
max , , 2 2 max ,
a
a
C
a
a
C
p C at Dax pC
Pmax= 0.5926 is the maximum of Betz!
We should call the Betz maximum the Betz-Youkowsky maximum, see G. van Kuik: The Lanchester–Betz–Joukowsky LimitHow can the Betz (Lanchester/Youkowsky) maximum be explained:
Force times velocity should be maximum!
2 Extremes:
V V V 1/3.V V= 0 V 2/3.VComplete blockage: Maximum force but local velocity equals zero
Completely transparant, no blocking:
Maximum velocity but Force equals zero
In between these extremes, an optimum situation exists
The maximum is reached when
Vd is 2/3 V and V4 = 1/3V
Results -2
Fill in a =1/3 to find the values of C
Pand C
Tat maximum energy
extraction condition:
Betz maximum
9
8
,
27
16
max , , max ,
DaxatCp
pC
C
Note
1.In literature the Betz maximum is often derived from the Bernouilli equation : • Bernouilli: p + 0.5 r V2 = constant.
• Since Bernouilli is derived from the conservation of energy it does not make any difference
Characterisation of rotor through Power coefficient C
P(Note the difference between mechanical and electrical C
P)
)
(
27
16
,
max 3 2 1V
A
C
Betz
P
C
P R p
r
DRotor shaft torque T, rotational speed Mechanical power Pmech = T Ω
Electrical power (generator): Pel = V I cos Φ
Velocity V Rotor Area AR = π /4 D2 Power coefficient = turbine power wind power
(a = 1/3)
24Example: Maximum power output
•
Calculate maximum mechanical power for:
–
Wind speed V = 10 m/s
–
Diameter D = 100 m
–
Sea level
•
Answer:
–
Sea level: r = 1.225 kg/m
3–
D = 100 m: Rotor area A
R= π/4 D
2= 7850 m
2–
Maximum power:
P
max= C
P,max0.5 ρ V
3A
R= 16/27 0.5 1.225 10
37850 = 2836793 W ~ 2.8 MW
NOTE
–
In practice: C
P< 16/27 (0.59): C
p,mech~ 0.5 C
P,el<0.5
The power coefficient (C
P) as function of tip speed ratio (l) is one of the
most important performance characteristics of a wind turbine
Free stream wind speed
Tip speed (m/s)
= Ω (in rad/s) x Blade length (m)
Jos Beurskens
Tip speed ratio (l)= Tip speed
Free stream wind speed
Tip speed ratio λ
• Tip speed of a wind turbine is usually in the order of 75 m/s
(=270 km/hr!!)
Note that the limitation of 75 m/s is mainly because of noise constraints):
• Large turbine (D = 100 m): 15 rpm
• Small turbine (D = 10 m): 150 rpm
(Note: • 1 revolution = 2π rad • 1 minute = 60 sec • 1 rpm = 2π/60 = ~0.1 rad/s)• So the tip speed for small wind turbines is about the same as the
tip speed for a large wind turbine but they make much more
revolutions per minute
• For such tip speed the tip speed ratio is 7.5 at a free stream
wind speed of 10 m/s
Representative C
P
-
λ curve
(Source TUDelft)• C
pmax• Corresponds to
a ~ 1/3
• Hence C
pmaxis still reached
at a
Betzeven
though C
pmax<C
PBetzC
PBetz0.59
28Contents
•
Principles of energy extraction, Betz-Lanchester
optimum
•
Design loads
•
Technology, state of the art
•
Wind Farm effects
•
Operation and Maintenance for Off-shore farms
• If you design a wind turbine the
DESIGN LOAD
SPECTRUM
should be calculated
• This represents the loads as experienced by a wind
turbine over its lifetime of 20 years.
• The (expected) external (wind) conditions are input to
these calculations.
• These external wind conditions are dictated by the
standards (usually IEC) and they are defined for
different wind speed classes with main parameters:
•
The (unknown) extreme wind speed over 50 years which is
assumed to be 5 times the (known) annual mean wind speed
•
‘Turbulence intensity’ (a measure for the variations in wind
speed)
DESIGN LOAD SPECTRUM
Definition of wind speed classes according to the
standard IEC 61400 ed.3
Vref: 10 minute extreme over 50 years Vave (hub height )= 0.2 Vref
A,B and C designate the categories for high, medium and low turbulence characteristics Iref is the expected value of the turbulence intensity at 15 m/s
Example: You measured at your site: Vave at hub height = 8.2 m/s and a turbulence intensity of 13% Vref = 5*8.2 = 41 m/s Class IIB
32 Turbine loads are determined by:
• aerodynamic and gravity forces
• structural dynamics of entire wind energy converter • rotor mass imbalance
• aerodynamic rotor imbalance
Turbine loads have to be determined over the
entire liftetime of a wind turbine (20 years) with an aero-elastic design code
Consider all operational conditions during the lifetime
(dictated by standards and determined by wind speed class): • normal operation (power production)
• start and stop (at Vcut-in and Vcut-out) • standstill
• failure (e.g. extreme yaw)
Design load spectrum
Loads calculated with
aero-elastic design code
Stochastic wind simulator
Turbulent characteristics (determined by wind class)
Aeroelastic code
V(y,z,t)
load
time Aeroelastic model description
Control model
Example of turbulent wind field calculated with
ECN’s stochastic wind simulator SWIFT
Calculation of a design spectrum
Short term
for each mean wind speed U (10 min.) repeat ~ 6 times (turbulence is stochastic!)
Long term
lifetime (20 years) Turbulence (U, I) random sea waves and current from Weibull distribution of U U m/s Nr 4-6 1.6e5 …. …. 8-10 1.7e5 …. …. 23-25 3.3e3 0 100 200 300 400 500 600 -3 -2 -1 0 1 2 3 4load time history
• Sum all 10 minute time series over the lifetime using the Weibull
distribution
• Add special load cases
• representative load time history over the lifetime
Force distribution on rotor blades
Aerodynamic forces in rotor plane are exerted by the moving
blades:
W
Wind speed
W
Torque
Power
rdr
f
Torque
rdr
f
M
rdr
f
M
dr
f
T
Thrust
blades R ip R ip inplane R oop plane of out blades R oop 3 0 0 0 0 foop fipNote:
• fip is ‘in-plane’ force;foop is ‘out-of-plane’ force;
• Mip is often called lead-lag or edgewise moment. Note Mip is mainly driven by gravity forces
• Moop is often called flap or flatwise moment
M
ipLong-term...fatigue loading of a rotor blade
Long-term...fatigue loading of a rotor blade
Long-term...fatigue loading of a rotor blade
Long-term...fatigue loading of a rotor blade
Max. flap moment Max. edge moment Min. flap moment Max. edge moment
(opposite direction) F la p m o m e n t Edge moment
Long-term...fatigue loading of a rotor blade
Long-term...fatigue loading of a rotor blade
Long-term...fatigue loading of a rotor blade
Long-term...fatigue loading of a rotor blade
F la p m o m e n t Edge moment
5-2-2019
41
https://upload.wikimedia.org/wikipedia/common s/6/61/De_Ambtenaar%2C_de_hoogste_windm olen_van_Europa_staat_bij_Medemblik._Zicht_
vanaf_de_MS_Friesland_03.jpg
Load on blade comparable to…
Load on blade comparable to…
Examples of external loads as function of time
for wind turbines
turbulence, gusts
wind shear
yaw
gravity loads on the
rotating blades
time time timeload
Blade load
load
T=2π/Ω
Courtesy: Wim Bierbooms
Contents
•
Principles of energy extraction, Betz-Lanchester
optimum
•
Design loads
•
Technology, state of the art
•
Wind Farm effects
•
Operation and Maintenance for Off-shore farms
Types
Jos Beurskens
• C
p,maxis more or less the same for all turbines but note:
• A Savonius turbine is a cheap but inefficient drag machine • The classical wind turbine has inefficient blades• Some of the aerodynamic losses decrease with where others increase with decreasing number of blades
Characterization of Rotors
P = T.Ω
(Remember: T = torque)
C
P=
P
½.ρ.V
3.A
r 45Characterization of Rotors
2 4 6 8 10
λ = 1
λ = 3
λ = 8
λ > 15
Hence: increases with decreasing number of blades!!
(Noisy like a jet fighter!)
Will the Vertical Axis Wind Turbines (VAWT) win?
•
Some people think that
VAWTS are economically
feasible at > 8MW
–
Generator down
–
No yawing system
–
No periodic variation of
gravity loads (although
variation of aerodynamic
loads is larger)
Source:Wikipedia
High altitude wind: kites or airplanes?
High altitude wind: kites or airplanes?
High altitude wind: kites or airplanes?
High altitude wind: kites or airplanes?
●
https://www.youtube.com/watch?v=NhoYL8xGRN
8&t=59s
Main characteristics of a horizontal
axis wind turbine
AREVA's 5 Megawatt Offshore movie
http://www.youtube.com/watch?v=6tM9wsOcEBM
Another one at:
http://www.youtube.com/watch?v=LNXTm7aHvWc
Main characteristics -1
•
Tower: Slightly conical steel tower, dimensioned
by overturning moment of rotor axial force
•
Yaw system between tower and nacelle, to yaw
rotor into the wind. Electrical or hydraulical, with
brakes. Controlled by wind vane on nacelle
•
Support structure for drive train, leads loads over
yaw system to tower
•
Drive train
–
With gearbox: main shaft between rotor hub and
gearbox, high speed shaft between gearbox and 2
pole-pair generator
–
‘direct drive’, no gearbox, but very large, slow,
multipole generator
•
Electrical frequency converter to enable
variable speed operation (AC-DC-AC)
•
Rotor with three blades (composites, glas fibre
epoxy or polyester) and pitch control with
electrical or hydraulic drives.
•
Cooling system for gearbox and generator
Main characteristics -2
REpower 5M with gearbox
Hub Rotor Bearings
Gearbox Converter
Transformer Generator Yaw System
Onboard-Crane
M
The nacelle, systems and components,
Repower 5M
Nacelle of direct drive wind turbine
Wind Turbine with Direct Drive
Generator
Enercon
E126
Number of blades
o First it should be known that more blades yield the maximum C
Pat a lower rotational speed
o 2 bladed rotor: relatively high Ω hence low torque and drive train
loads (P=TΩ) and a relatively low gear ratio for electricity
generating turbines with Ω
gen= 1500 rpm
Gear box Gear ratio: Ωgenerator/Ωrotor Ωrotor~10-20 rpm Ωgenerator ~ 1500 rpm 58
Why 3 blades instead of 2 blades *)
•
Pro’s 3 blades
–
Lower rotational speed Less noise
–
Better visual impact
–
‘Smoother’ loading over a revolution
•
Pro’s 2 blades
–
Higher rotational speed lower torque, smaller gear ratio
–
Less blades( lower costs)
•
Conclusion: 2 Bladed turbines may be preferred from a
technological/economical point of view but they will
never be sold (at least not for on-shore conditions,
they may be an option for off-shore
*) Note: Multi-bladed water pumpers have a very low W and hence a
(desirable) high torque (P=WQ) water pumpers
Contents
•
Principles of energy extraction, Betz-Lanchester
optimum
•
Design loads
•
Technology, state of the art
•
Wind Farm effects
•
Operation and Maintenance for Off-shore farms
(Off-shore) farms
• Example:
– Hornsrev windfarm (DK) on a humid day
• Wind farm effects: – Losses
wind farm efficiency 85-95% – Increase in mechanical loading on
turbines in farm u increased turbulence reduced windspeed turbine wake Wind farm effects dependent on wind direction:
– Five 2.5MW research turbines N80 with one 108m high meteorological mast
– Five locations for prototype turbines with meteorological masts (108m)
– Measurement Infrastructure – Measurement Pavilion
ECN Wind Turbine Test site Wieringermeer (EWTW)
- Scale Wind farm
Intermezzo: ECN Wind Turbine Test Site Wieringermeer
ECN Wind Turbine Test site Wieringermeer, EWTW
– State of the art turbines – Research farm
– Turbine data available
See also:
http://www.youtube.com/watch?v=mhSOeF6-ut8
Contents
•
Principles of energy extraction
•
Fundamental Equations, momentum theory for
an actuator disk
•
Betz-Lanchester optimum
•
Design loads
•
Technology, state of the art
•
Wind Farm effects
•
Operation and Maintenance for Off-shore farms
www.we-at-sea.org
What makes offshore
different from onshore ?
Offshore WE technology: What makes it different
from land based applications?
• Cost breakdown
• External conditions
(waves, salt conditions, turbulence, extreme winds, (sea) bottom)• Support structures
• Transport and Assembly
• Commissioning
• Operation and Maintenance; Access
• Grid integration
• Scale & Risk
• Nature issues & Safety
2012-05 www.we-at-sea.org 66
Specific Offshore issues
Why is O&M offshore so difficult?
Availability
of off-shore wind farms
Availability = f (reliability, accessibility)
Availability
100% accessibility (onshore) 80% accessibility 60% accessibility 40% accessibility (exposed offshore) 50 60 70 80 90 100state-of-the-art improved highly improved
Reliability of design [-] O W EC S A va ila b ili ty [ % ]
Strategy 1
Ampelmann: 2 Hs= 2 m, 50 m vessel (85 %) 69Johannes Christiaan Schotel, Stormy weather- 1813
Edward William Cooke, 1811-1880
Offshore
Peace and quiet…
So why is offshore O&M so difficult and
expensive?
http://www.youtube.com/watch?v=i9sBA3JGWj4
Personnel & Spare Parts: > 2 – 5 k€ / access
(80 – 120 k€ / day)
Availability/accessibility
www.we-at-sea.org
Operation and Maintenance
Access technology
Photo: Jos BeurskensFoto: Jos Beurskens
Foto: Jos Beurskens
Ampelmann concept
Availability/accessibility: Ampelmann
(J. vd Tempel)
www.we-at-sea.org 77
Operation and Maintenance
Reliability: Components, damaged
Data, timeseries 0.0 5.0 10.0 15.0 20.0 25.0 0 30 60 90 120 150 180 210 240 270 300 Time [hrs] W in d sp ee d [m /s ] 0.00 1.00 2.00 3.00 4.00 5.00 W av e he ig ht [ m ]
Wind speed [m/s] (Upper limit) Vref
Hm0 [m] (Upper limit) Href
Failure
Repair time for mission of 40 resp. 20 hr?
Hs = 1,5 m Vw = 12 m/s
T_wait40 hr = 96 hr in operation:136 hr
In Operation
T_wait 20 hr = 56 hrin operation:76 hr
In Operation
Availability/reliability (O&M)
ECN; Braam, Rademakers