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Measure and Integration (WISB-312) 3rd of July 2007

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Institute of Mathematics, Faculty of Mathematics and Computer Science, UU.

Made available in electronic form by the TBC of A–Eskwadraat In 2006/2007, the course WISB-312 was given by K. Dajani.

Measure and Integration (WISB-312) 3rd of July 2007

Question 1

Consider the measure space (R, B(R), λ), where B(R) is the Borel σ-algebra, and λ the Lebesgue measure.

a) Let f ∈ L1(λ). Show that for all a ∈ R, one has Z

R

f (x − a)dλ(x) = Z

R

f (x)dλ(x)

b) Let k, g ∈ L1(λ). Define F : R2→ ¯R by

F (x, y) = k(x − y)g(y) and h(x) = Z

R

F (x, y)dλ(y).

• Show that F is measurable.

• Show that

Z

R

|h(x)|dλ(x) ≤

Z

R

|k(x)|dλ(x)

 Z

R

|g(y)|dλ(y)



and λ(|h| = ∞) = 0.

Question 2

Consider the measure space ((0, ∞), B((0, ∞)), λ), where B((0, ∞)) and λ are the restrictions of the Borel σ-algebra and the Lebesgue measure to the interval (0, ∞). Show that

n→∞lim Z

(0,n)

 1 +x

n

n

e−2xdλ(x) = 1.

Question 3

Let (X, A, µ) be a probability space (i.e. µ(X) = 1).

a) Suppose 1 ≤ p < r, and fn, f ∈ Lr(µ) satisfy limn→∞kfn− f kr= 0. Show that

n→∞lim kfn− f kp= 0.

b) Assume p, q > 1 satisfy 1p+1q = 1. Suppose fn, f ∈ Lp(µ), and gn, g ∈ Lq(µ) satisfy

n→∞lim kfn− f kp = lim

n→∞kgn− gkq = 0 Show that lim

n→∞kfngn− f gk1= 0.

Question 4

Let 0 < a < b. Prove with the help of Tonelli’s theorem (applied to the function f (x, t) = e−xtthat R

[0,∞)(e−at− e−bt)1tdλ(t) = log(b/a), where λ denotes the Lebesgue measure.

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Question 5

Let (X, A, µ1) and (Y, B, ν1) be measure spaces. Suppose f ∈ L11) and g ∈ L11) are non-negative.

Define measures µ2 on A and ν2 on B by µ2(A) =

Z

A

f dµ1 and ν2(B) = Z

B

g dν1,

for A ∈ A and B ∈ B.

a) For D ∈ A ⊗ B and y ∈ Y , let Dy = {x ∈ X : (x, y) ∈ D}. Show that if µ1(Dy) = 0 ν1-a.e., then µ2(Dy) = 0 ν2-a.e.

b) Show that if D ∈ A ⊗ B is such that (µ1× ν1)(D) = 0 then (µ2× ν2)(D) = 0.

c) Show that for every D ∈ A ⊗ B one has (µ2× ν2)(D) =

Z

D

f (x)g(y) d(µ1× ν1)(x, y).

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