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 World Scientific Publishing Company DOI: 10.1142/S0218196721500065

An extension of the Glauberman ZJ-theorem

M. Yasir Kızmaz Department of Mathematics

Bilkent University, 06800 Bilkent, Ankara, Turkey yasirkizmaz@bilkent.edu.tr

Received 26 September 2019 Accepted 4 September 2020 Published 30 October 2020 Communicated by O. Kharlampovich

Let p be an odd prime and let Jo(X), Jr(X) and Je(X) denote the three different versions of Thompson subgroups for a p-group X. In this paper, we first prove an extension of Glauberman’s replacement theorem [G. Glauberman, A characteristic sub- group of ap-stable group, Canad. J. Math. 20 (1968) 1101–1135, Theorem 4.1]. Sec- ond, we prove the following: Let G be a p-stable group and P ∈ Sylp(G). Suppose that CG(Op(G)) ≤ Op(G). If D is a strongly closed subgroup in P , then Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) are normal subgroups of G. Third, we show the follow- ing: LetG be a Qd(p)-free group and P ∈ Sylp(G). If D is a strongly closed subgroup in P , then the normalizers of the subgroups Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) con- trol strongG-fusion in P . We also prove a similar result for a p-stable and p-constrained group. Finally, we give ap-nilpotency criteria, which is an extension of Glauberman–

Thompsonp-nilpotency theorem.

Keywords: Controlling fusion; ZJ-theorem; p-stable groups.

Mathematics Subject Classification 2020: 20D10, 20D20

1. Introduction

Throughout the paper, all groups considered are finite. Let P be a p-group. For each abelian subgroup A of P , let m(A) be the rank of A, and let dr(P ) be the maximum of the numbers m(A). Similarly, do(P ) is defined to be the maximum of orders of abelian subgroups of P and de(P ) is defined to be the maximum of orders of elementary abelian subgroups of P . Define

Ao(P ) ={A ≤ P | A is abelian and |A| = do(P )}, Ar(P ) ={A ≤ P | A is abelian and m(A) = dr(P )} and

Ae(P ) ={A ≤ P | A is elementary abelian and |A| = de(P )}.

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Now we are ready to define three different versions of Thompson subgroup: Jr(P ), Jo(P ) and Je(P ) are subgroups of P generated by all members ofAr(P ),Ao(P ) andAe(P ), respectively. These definitions appear in [2] with the same notations.

Thompson proved his normal complement theorem according to Jr(P ) in [13], which states: Let G be a group and P ∈ Sylp(G). If NG(Jr(P )) and CG(Z(P )) are both p-nilpotent and p is odd, then G is p-nilpotent. Later Thompson introduced “a replacement theorem” and a subgroup similar to Jo(P ) in [14]. Glauberman gener- alized the replacement theorem of Thompson for odd primes (see [2, Theorem 4.1]) and worked with Jo(P ) in [2] due to the compatibility of the replacement theorem with Jo(P ). We should note that Glauberman’s replacement theorem is one of the important ingredients of the proof of Glauberman ZJ-theorem [2, Theorem A].

Definition ([3, p. 22]). A group G is called p-stable if it satisfies the following condition: Whenever U is a p-subgroup of G, g∈ NG(U ) and [U, g, g] = 1 then the coset gCG(U ) lies in Op(NG(U )/CG(U )).

Now we are ready to state Glauberman ZJ-theorem.

Theorem (Glauberman). Let p be an odd prime, G be a p-stable group, and P ∈ Sylp(G). Suppose that CG(Op(G))≤ Op(G). Then Z(Jo(P )) is a characteristic subgroup of G.

There are many important consequences of the above theorem. A striking one is that NG(Z(Jo(P ))) controls strong G-fusion in P when G does not involve a subquotient isomorphic to Qd(p) (see [2, Theorem B]). Note that Qd(p) is defined to be a semidirect product ofZp×Zpwith SL(2, p) by the natural action of SL(2, p) onZp× Zp. Another consequence of Glauberman ZJ-theorem is an improvement of Thompson normal complement theorem. This result says that if NG(Z(Jo(P ))) is p-nilpotent and p is odd, then G is p-nilpotent (see [2, Theorem D]).

There is still active research on the properties of Thompson’s subgroups. A cur- rent paper [12] is describing algorithms for determining Je(P ) and Jo(P ). We also refer to [12, 10] for more extensive discussions about literature and replacement theorems, which we do not state here. It deserves to be mentioned separately that Glauberman obtained remarkably more general versions of the Thompson replace- ment theorem in his later works (see [4, 5]). We should also note that even if [12, Theorem 1] is attributed to Thompson replacement theorem [13] in [12], it seems that the correct reference is Isaacs replacement theorem (see [9]).

In [1], the ZJ-theorem is given according to Je(P ) (see [1, Theorem 1.21, Defi- nition 1.16]). Although it might be natural to think that Glauberman ZJ-theorem is also correct for “Je(P ) and Jr(P )”, there is no reference verifying that. How- ever, we should mention that Stellmacher showed that there exists a characteristic subgroup W of P such that Ω(Z(P ))≤ W ≤ Ω(Z(Je(P ))) and W satisfies the con- clusion of Glauberman’s theorem (see [11, Theorem 9.4.4]). The relations between Glauberman ZJ-theorem and spherical fibrations over classifying spaces are studied Int. J. Algebra Comput. Downloaded from www.worldscientific.com by BILKENT UNIVERSITY on 11/28/20. Re-use and distribution is strictly not permitted, except for Open Access articles.

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in [15, Sec. 3]. Moreover, it is observed in [15] that Je(P ) is more useful to investi- gate these relations. This particular case shows that different Thompson subgroups may have distinct applications. This is one of our motivations to prove our extension of Glauberman ZJ-theorem (Theorem B) for all versions of Thompson’s subgroups.

One of the purposes of this paper is to generalize Glauberman replacement theorem (see [2, Theorem 4.1]), which was used in the proof of Glauberman ZJ- theorem. We also note that our replacement theorem is an extension of Isaacs replacement theorem (see [9]) when we consider odd primes. The following is the first main theorem of our paper.

Theorem A. Let G be a p-group for an odd prime p and A≤ G be abelian. Suppose that B≤ G is of class at most 2 such that B ≤ A, A ≤ NG(B) and B NG(A).

Then there exists an abelian subgroup A of G such that (a) |A| = |A|,

(b) A∩ B < A∩ B, (c) A≤ NG(A)∩ AG,

(d) the exponent of A divides the exponent of A. Moreover, rank(A)≤ rank(A).

One of the main differences from [2, Theorem 4.1] is that we are not taking A to be of maximal order. By removing the order condition, we obtain more flexibility to apply the replacement theorem. Since our replacement theorem is easily applicable to all versions of Thompson subgroups and there is a gap in the literature whether the ZJ-theorem holds for other versions of Thompson subgroups, we shall prove our extensions of Glauberman ZJ-theorem for all different versions of Thompson subgroups.

Definition 1.1. Let G be a group, P ∈ Sylp(G), and D be a nonempty subset of P . We say that D is a strongly closed set in P (with respect to G) if for all U ⊆ D and g ∈ G such that Ug ⊆ P , the containment Ug ⊆ D holds. In the case that D is a subgroup of P , D is said to be a strongly closed subgroup.

Let K be a p-group. We write Ωi(K) to denote the subgroup{x ∈ K | xpi = 1}

of K for i ∈ Z+ and we simply use Ω(K) in place of Ω1(K). Here is the second main theorem of the paper.

Theorem B. Let p be an odd prime, G be a p-stable group, and P ∈ Sylp(G).

Suppose that CG(Op(G)) ≤ Op(G). If D is a strongly closed subgroup in P then Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) are normal subgroups of G.

We prove Theorem B by mainly following the original proof given by Glauber- man and with the help of Theorem A. When we take D = P , we obtain that Z(Jo(P )), Ω(Z(Jr(P ))) and Ω(Z(Je(P ))) are characteristic subgroups of G under the hypothesis of Theorem B. Both Z(Jr(P )) and Z(Je(P )) need an extra opera- tion “Ω” and it does not seem quite possible to remove “Ω” by the method used here.

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Definition ([6, p. 268]). A group G is called p-constrained if CG(Y )≤ Op,p(G) for a Sylow p-subgroup Y of Op,p(G).

Theorem C. Let p be an odd prime, G be a p-stable group, and P ∈ Sylp(G).

Assume that NG(U ) is p-constrained for each nontrivial subgroup U of P . If D is a strongly closed subgroup in P then the normalizers of the subgroups Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) control strong G-fusion in P .

Remark 1.2. In [7], it is shown that if G is p-stable and p > 3 then G is p-constrained and the proof uses the classification of finite simple groups (see [7, Proposition 2.3]). Note that a subgroup of a p-stable group is also p-stable (see Lemma 3.10), and so NG(U ) is p-stable. Hence, the assumption “NG(U ) is p-constrained for each nontrivial subgroup U of P ” is automatically satisfied when p > 3 and G is a p-stable group.

Theorem D. Let p be an odd prime, G be a Qd(p)-free group, and P ∈ Sylp(G). If D is a strongly closed subgroup in P then the normalizers of the subgroups Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) control strong G-fusion in P .

Remark 1.3. In Theorem D, if we take D = P , then the proof of this special case follows by Theorem B and [3, Theorem 6.6]. However, the general case requires some extra work. We shall define the concept “the localization of a conjugacy functor”

(see Definition 4.3) and deduce some of its properties (see Lemmas 4.4, 4.6 and 4.8).

These are used in the proofs of Theorems C, D and E.

Lastly, we state an extension of Glauberman–Thompson p-nilpotency theorem.

Theorem E. Let p be an odd prime, G be a group and P ∈ Sylp(G). If D is a strongly closed subgroup in P then G is p-nilpotent if one among the normalizer of the subgroups Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) is p-nilpotent.

Remark 1.4. Let G be a group, P ∈ Sylp(G) and D be a strongly closed subgroup in P . Assume that Ωi(D) is of exponent at most pifor some i. Then it is routine to check that Ωi(D) is also strongly closed subgroup in P . In Theorems B, C, D and E if we write Ωi(D) in place of D (under the above assumption), we can obtain some variations of these theorems. We should note that the assumption is automatically satisfied when D is a regular p-group.

2. The Proof of Theorem A

We start with a lemma whose proof is extracted from the proof of Glauberman replacement theorem.

Lemma 2.1 (Glauberman). Let p be an odd prime and G be a p-group. Suppose that G = BA where B is a normal subgroup of G such that B ≤ Z(G) and A is an abelian subgroup of G such that [B, A, A, A] = 1. Then [b, A] is an abelian subgroup of G for each b∈ B.

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Proof. Let x, y∈ A. Our aim is to show that [b, x] and [b, y] commute. Set u = [b, y].

If we apply the Hall–Witt identity to the triple (b, x−1, u), we obtain that [b, x, u]x−1[x−1, u−1, b]u[u, b−1, x−1]b= 1.

Note that the above commutators of weight 3 lie in the center of G since B is normal in G and B ≤ Z(G). Thus, we may remove conjugations in the above equation. Moreover, [u, b−1, x−1] = 1 as [u, b−1]∈ B. Thus, we obtain that [b, x, u][x−1, u−1, b] = 1, and so

[b, x, u] = [x−1, u−1, b]−1. Since [x−1, u−1, b] = [[x−1, u−1], b]∈ Z(G), we see that

[x−1, u−1, b]−1= [[x−1, u−1], b]−1 = [[x−1, u−1]−1, b] = [[u−1, x−1], b]

by [6, Lemma 2.2.5(ii)]. As a consequence, we get that [b, x, u] = [[u−1, x−1], b]. By inserting u = [b, y], we obtain

[[b, x], [b, y]] = [[[b, y]−1, x−1], b].

Now set G = G/B. Then clearly B is abelian. It follows that [B, A, A]≤ Z(G) since G = AB, [B, A, A, A] = 1 and B is abelian. Then we have

[[b, y]−1, x−1]≡ [[b, y]−1, x]−1 ≡ [[b, y], x] mod B

by applying [6, Lemma 2.2.5(ii)] to G. Since x and y commute and [b, G] ⊆ B is abelian, we see that

[b, y, x]≡ [b, x, y] mod B by [6, Lemma 2.2.5(i)].

Since B ≤ Z(G), we obtain

[[b, x], [b, y]] = [[[b, y]−1, x−1], b] = [[[b, y], x], b] = [[b, x, y], b].

By symmetry, we also have that [[b, y], [b, x]] = [[b, x, y], b]. Then it follows that [[b, y], [b, x]] = [[b, y], [b, x]]−1, and so [[b, x], [b, y]] = 1 since G is of odd order.

Lemma 2.2. Let A be an abelian p-group and E be the largest elementary abelian subgroup of A. Then rank(E) = rank(A).

Proof. Consider the homomorphism φ : A → A by φ(a) = ap for each a ∈ A.

Note that φ(A) = Φ(A) and E = Ker(φ), and so |A/Φ(A)| = |E|. Since both E and A/Φ(A) are elementary abelian groups of same order, we get rank(E) = rank(A/Φ(A)). On the other hand, rank(A/Φ(A)) = rank(A) and the result follows.

Proof of Theorem A. We proceed by induction on the order of G. We can certainly assume that G = AB. Since A is not normal in G, there exists a maximal subgroup M of G such that A≤ M.

Clearly A normalizes M ∩ B as both M and B are normal in G. Suppose that M∩ B does not normalize A. By induction applied to M, there exists a subgroup Int. J. Algebra Comput. Downloaded from www.worldscientific.com by BILKENT UNIVERSITY on 11/28/20. Re-use and distribution is strictly not permitted, except for Open Access articles.

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A of M such that Asatisfies the conclusion of the theorem. Then Aalso satisfies (a), (c) and (d) in G. Moreover, A∩ (M ∩ B) = A ∩ B < A∩ B, and so G also satisfies the theorem. Hence, we can assume that M ∩ B ≤ NG(A). Note that M = M∩ AB = A(M ∩ B), and so M = NG(A).

Clearly M∩ B is a maximal subgroup of B. Then A acts trivially on B/(M ∩ B), and so [B, A] ≤ M = NG(A). Thus, we see that [B, A, A] ≤ A which yields [B, A, A, A] = 1. Moreover, we have that B ≤ Z(G) since B≤ A and B≤ Z(B).

It follows that [b, A] is abelian for any b∈ B by Lemma 2.1.

Let b∈ B\M. Then A = Ab M. Set H = AAb and Z = A∩ Ab. Then clearly H is a group and Z≤ Z(H). On the other hand, H is of class at most 2 since H/Z is abelian. Note that the identity (xy)n = xnyn[x, y]n(n−1)2 holds for all x, y ∈ H as H is of odd order and [H, H] ≤ Z(H) by [6, Lemma 2.2.2]. It follows that the exponent of H is the same as the exponent of A.

Next, we shall show that H∩ B is abelian. First we claim that H ∩ B = (A ∩ B)[b, A]. Clearly, we have [b, A] ⊆ H ∩ B since H = AAb. It follows that (A∩ B)[b, A] ⊆ H ∩ B as A ∩ B ≤ H ∩ B. Next, we obtain the reverse inequality. Let x ∈ H ∩ B. Then x = acb for a, c ∈ A such that acb ∈ B. Since B  G, we see that [c, b]∈ B, and so ac ∈ B as ac[c, b] = acb∈ B. It follows that ac ∈ A ∩ B and x = ac[c, b]∈ (A ∩ B)[b, A], which proves the equality H ∩ B = (A ∩ B)[b, A]. Since B ≤ A, we see that A ∩ B  B. Then A ∩ B = Ab∩ B and hence A ∩ B = Z ∩ B. In particular, we see that A∩ B ≤ Z ≤ Z(H). It follows that H ∩ B = (A ∩ B)[b, A]

is abelian since [b, A] is an abelian subgroup of H and (A∩ B) ≤ Z(H).

Set A= (H∩B)Z. Note that Ais abelian as H∩B is abelian and Z ≤ Z(H).

Now we shall show that A is the desired subgroup. Clearly, the exponent of A divides the exponent of H, which we showed is equal to the exponent of A, and so the first part of (d) follows. Note that A < H and H = H∩ AB = A(H ∩ B), and so H∩ B > A ∩ B. It follows that A∩ B ≥ H ∩ B > A ∩ B, which shows (b). On the other hand,

A≤ H = AAb≤ M ∩ AG= NG(A)∩ AG,

which shows (c). It remains to prove (a) and the second part of (d). Since A = (H∩ B)Z, we have

|A| = |H ∩ B||Z|

|Z ∩ B| = |H ∩ B||Z|

|A ∩ B| . As H = AAb= A(H∩ B), we obtain that

|AAb|

|Ab| = |A(H ∩ B)|

|A| =|H ∩ B|

|A ∩ B|. On the other hand, we see that

|AAb|

|Ab| = |A|

|A ∩ Ab| = |A|

|Z|. Thus, we get the equality|A| = |A| as desired.

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Let E be the largest elementary abelian subgroup of A. We shall observe that E and A enjoy some similar properties. Note that E M = NG(A) since E is a characteristic subgroup of A. Hence, EEb is a group. Set H1= EEb, Z1= E∩ Eb and E = (H1∩ B)Z1. First observe that Z1 ≤ Z(H1), and so H1 is of class at most 2. It follows that the exponent of Eis p since H1is of odd order. Thus, Eis elementary abelian as E≤ Aand Ais abelian. Note also that E∩B = E∩(A∩B), and so E∩ B is characteristic in A ∩ B. Then we see that E ∩ B  B as A ∩ B  B.

This also yields that E∩ B = (E ∩ B)b = Eb ∩ B, and hence E ∩ B = Z1∩ B.

Finally, observe that H1= EEb = EEb∩ EB = E(H1∩ B). Now we can show that

|E| = |E| by using the same method used for showing that |A| = |A|. Then we see that rank(A) = rank(E) = rank(E)≤ rank(A) by Lemma 2.2.

3. The Proof of Theorem B

Lemma 3.1. Let P be a p-group and R be a subgroup of P . Then if there exists A ∈ Ax(P ) such that A ≤ R then Jx(R) ≤ Jx(P ) for x ∈ {o, r, e}. Moreover, Jx(P ) = Jx(R) if and only if Jx(P )≤ R for x ∈ {o, r, e}.

Proof. Let A⊆ R for some A ∈ Ax(P ). Note thatAx(R)⊆ Ax(P ) by the defini- tion ofAx(P ) for each x∈ {o, r, e}, and so Jx(R)≤ Jx(P ) in that case.

Next observe that Jx(P )≤ R if and only if Ax(P ) =Ax(R). Then the second part follows.

Lemma 3.2 ([6, Theorem 8.1.3]). Let G be a p-stable group such that CG(Op(G)) ≤ Op(G). If P ∈ Sylp(G) and A is an abelian normal subgroup of P then A≤ Op(G).

Proof. Since Op(G) normalizes A, we see that [Op(G), A, A] = 1. Write C = CG(Op(G)). Then we have AC/C ≤ Op(G/C). Note that Op(G/C) = Op(G)/C since C≤ Op(G). It follows that A≤ Op(G).

Lemma 3.3. Let G be a group and P ∈ Sylp(G). Suppose that D is a strongly closed subset in P . If N G and D ∩ N is nonempty then D ∩ N is also a strongly closed subset in P . Moreover, G = NG(D∩ N)N.

Proof. Write D= D∩ N. Let U ⊆ D and g∈ G such that Ug⊆ P . It follows that Ug ⊆ D as U ⊆ D and D is strongly closed in G. Since N  G, we see that Ug⊆ N which yields that Ug⊆ N ∩ D = D which shows the first part.

Let Q = P ∩ N. Then we see that Q ∈ Sylp(N ), and so G = NG(Q)N by the Frattini argument. Thus, it is enough to show that NG(Q) ≤ NG(D). Let x∈ NG(Q). Then Dx ⊆ Q ≤ P . Since D is strongly closed in P , we see that D∗x= D. It follows that x∈ NG(D), as desired.

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Lemma 3.4. Let P be a p-group, p be odd, and let B, N P . Suppose that B is of class at most 2 and B≤ A for all A ∈ Ax(N ). Then there exists A∈ Ax(N ) such that B normalizes A while x∈ {o, r, e}.

Proof. Choose A ∈ Ax(N ) such that A∩ B has the maximum possible order.

Assume that B does not normalize A. Then there exists an abelian subgroup A≤ P such that |A| = |A|, A ≤ AP ∩ NP(A), A∩ B < A∩ B, the exponent of A divides that of A and rank(A)≤ rank(A) by Theorem A. Since A≤ N  P , we see that A≤ AP ≤ N.

We claim that A ∈ Ax(N ) for x∈ {o, r, e}. In the case that x = o, the claim is obviously true as |A| = |A|. Let x = e. Since the exponent of A divides the exponent of A and A is elementary abelian, we see that A is also elementary abelian. That yields that A ∈ Ae(N ) as |A| = |A|. Now suppose that x = r.

We see that rank(A) = rank(A) as rank(A) ≥ rank(A) and the rank of A is the maximum possible in N . Then we get that A ∈ Ar(N ). So, A ∈ Ax(N ) for x ∈ {o, r, e}, contradicting the maximality of |A ∩ B|. Thus, B normalizes A as desired.

Notation 3.5. Let P be a p-group. We denote the following subgroups Z(Jo(P )), Ω(Z(Jr(P ))) and Ω(Z(Je(P ))) of P by Zo(P ), Zr(P ) and Ze(P ), respectively.

Lemma 3.6. Let P be a p-group. Then Zx(P ) ≤ A for all A ∈ Ax(P ) while x∈ {o, r, e}.

Proof. Let Z = Zx(P ). Since Z ≤ Z(Jx(P )) and A≤ Jx(P ), we see that ZA is an abelian subgroup of P . If x = o, then ZA≤ A as A is a maximal abelian subgroup of P . Thus, Z ≤ A. In the case that x = r, we again obtain that Z ≤ A as A has the maximum possible rank in P and Z = Ω(Z(Jr(P ))) is elementary abelian. Now let x = e. We see that ZA is elementary abelian as both Z and A are elementary abelian. So, Z ≤ A as A is a maximal elementary abelian subgroup of P .

Theorem 3.7. Let p be an odd prime, G be a p-stable group, and P ∈ Sylp(G).

Let D be a strongly closed subset in P and B be a normal p-subgroup of G. Write K =D. If all members of Ax(K) are included in D then Zx(K)∩ B  G while x∈ {o, r, e}.

Proof. Fix x∈ {o, r, e}. Write J(U) = Jx(U ) for any p-subgroup U of P and set Z = Zx(K). We can clearly assume that B= 1. Let G be a counter example, and choose B to be the smallest possible normal p-subgroup contradicting the theorem.

As D is strongly closed in P , it is a normal subset of P . It then follows that

D = K  P , and so Z  P . In particular, B normalizes Z.

Set B1 = (Z∩ B)G. Clearly B1 ≤ B. Suppose that B1 < B. By our choice of B, we get Z∩ B1 G. Since Z ∩ B ≤ B1, we have Z∩ B ≤ Z ∩ B1≤ Z ∩ B, and hence Z∩ B = Z ∩ B1. This contradiction shows that B = B1= (Z∩ B)G. Int. J. Algebra Comput. Downloaded from www.worldscientific.com by BILKENT UNIVERSITY on 11/28/20. Re-use and distribution is strictly not permitted, except for Open Access articles.

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Clearly B < B, and hence Z∩ B  G by our choice of B. Since Z and B normalize each other, [Z∩ B, B] ≤ Z ∩ B. Since B and Z∩ B are both normal subgroups of G, we obtain [(Z ∩ B)g, B] ≤ Z ∩ B for all g ∈ G. This yields [(Z∩ B)G, B] = [B, B] = B ≤ Z ∩ B. In particular, we have B ≤ Z, and so [Z∩ B, B] = 1. It follows that [B, B] = 1 as B = (Z∩ B)G. As a consequence, we see that B is of class at most 2. Note that Z≤ A for all A ∈ Ax(K) by Lemma 3.6.

In particular, B≤ A for all A ∈ Ax(K).

Let N be the largest normal subgroup of G that normalizes Z ∩ B. Set D= D∩N. Note that all members of Ax(K) are included in D by the hypothesis, and so the identity element lies in D. Thus, D is nonempty. Write K =D.

We see that G = NG(D)N by Lemma 3.3, and so G = NG(K)N . It follows that G = NG(J (K))N since J (K) is a characteristic subgroup of K. Suppose that J (K) ≤ K. Then we see that J (K) = J (K), and hence Z∩ B is nor- malized by NG(J (K)). It follows that Z ∩ B  G. Thus, we may assume that J (K) K.

There exists A ∈ Ax(K) such that B normalizes A by Lemma 3.4. Hence, [B, A, A] = 1 as [B, A]≤ A. Since G is p-stable and B  G, we have that AC/C ≤ Op(G/C), where C = CG(B). Note that C normalizes Z∩ B, and so C ≤ N by the choice of N . It follows that AN/N≤ Op(G/N ). Now we claim that Op(G/N ) = 1.

Let LG such that L/N = Op(G/N ). Then L = (L∩P )N, and hence L normalizes Z∩ B as both N and L ∩ P normalize Z ∩ B. The maximality of N forces that N = L, which yields that Op(G/N ) = 1. Thus, A ≤ N. Note that A ⊆ D by hypothesis, and so A⊆ N ∩ D = D⊆ K.

We see that Z≤ A ≤ J(K), and so we have J (K)≤ J(K) and Z ≤ Z(J(K)).

It follows that Z∩ B ≤ Z ≤ Zx(K). Set U = Zx(K). Then we see that G = N NG(U ) since G = N NG(K) and U is characteristic in K. As N normalizes Z∩ B, each distinct conjugate of Z ∩ B comes via an element of NG(U ). Thus, B = (Z∩ B)G = (Z∩ B)NG(U)≤ U.

Since J (K)  K, some members of Ax(K) do not lie in K. Among such members, choose A1∈ Ax(K) such that A1∩ B has the maximum possible order.

Note that B does not normalize A1, since otherwise this forces A1 ≤ K as in previous paragraphs. Then there exists A ≤ P such that |A| = |A1|, A AP1 ∩ NP(A1), A1∩ B < A ∩ B, the exponent of A divides that of A1 and rank(A1) ≤ rank(A) by Theorem A. Note that A ≤ K as AP1 ≤ K  P . The order, rank and the exponent of A force that A ∈ Ax(K) for x ∈ {o, r, e}. It follows that A≤ K due to the choice of A1, and so A ∈ Ax(K). We see that B≤ U = Zx(K)≤ Aby Lemma 3.6. It follows that B≤ A≤ NP(A1), which is the final contradiction.

When we work with Jo(K), we do not need to use Ω operation due to the fact that Z(Jo(K))≤ A for all A ∈ Ao(K). However, this does not need to be satisfied for Z(Je(K)) and Z(Jr(K)). This difference causes the use of Ω operation necessary for Z(Je(K)) and Z(Jr(K)).

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Proof of Theorem B. As in our hypothesis, let p be a odd prime, G be a p-stable group such that CG(Op(G)) ≤ Op(G) and D be a strongly closed subgroup in P . Since all these subgroups Z(Jo(D)), Ω(Z(Jr(D))) and Ω(Z(Je(D))) are abelian normal subgroups of G, we see that they must be included in Op(G) by Lemma 3.2.

Note that D is also a strongly closed subset in P and satisfies the hypothesis of Theorem 3.7. Then the results follow from Theorem 3.7, applied with B = Op(G).

As an application of Theorem 3.7, we prove the following theorem, which we shall need in the next section.

Theorem 3.8. Let p be an odd prime, G be a p-stable and p-constrained group, and P ∈ Sylp(G). Let D be a strongly closed subset in P . Write K = D. If all members ofAx(K) are included in D, then the normalizer of Zx(K) controls strong G-fusion in P while x∈ {o, r, e}.

We need the following lemma in the proof of Theorem 3.8.

Lemma 3.9 ([2, Lemma 7.2]). If G is a p-stable group, then G/Op(G) is also p-stable.

Since the p-stability definition we used here is not same with that of [2] and [2, Lemma 7.2] has also the extra assumption that Op(G)= 1, it is appropriate to give a proof of this lemma here.

Proof. Write N = Op(G) and G = G/N . Let V be p-subgroup of G. Then there exists a p-subgroup U of G such that U = V .

Let x∈ NG(U ) such that [U , x, x] = 1. Clearly, we can write x = x1x2such that x1is a p-element, x2is a p-element and [x1, x2] = 1 for some x1, x2∈ G. It follows that [U , xi, xi] = 1 for i = 1, 2. Then we see that x2∈ CG(U ) by [8, Lemma 4.29].

Thus, it is enough to show that x1∈ Op(NG(U )/CG(U )) to finish the proof.

Since x1 is a p-element of G, x1 = sn where n∈ N and s is a p-element of G, which yields that x1 = s. Then we see that [U N, s, s] ∈ N and s ∈ NG(U N ) by the previous paragraph. Note that U ∈ Sylp(U N ) and |Sylp(U N )| is a p-number.

Consider the action ofs on Sylp(U N ). Then we observe that s normalizes Unfor some n∈ N. Thus, we get that [Un, s, s]≤ Un∩ N = 1. Note that U = Un, and so we take Un = U without loss of generality.

Let K ≤ NG(U ) such that K/CG(U ) = Op(NG(U )/CG(U )). Thus we observe that s∈ K as G is p-stable. Note that NG(U ) = NG(U ) and CG(U ) = CG(U ) by [8, Lemma 7.7]. Hence, we see that x1= s∈ K and K/CG(U )≤ Op(NG(U )/CG(U )) = Op(NG(U )/CG(U )), which completes the proof.

Proof of Theorem 3.8. Write G = G/Op(G). Then G is p-stable by Lemma 3.9.

Since G is p-constrained, we have CG(Op(G))≤ Op(G) by [6, Theorem 1.1(ii)]. Note that Zx(K) ≤ Op(G) by Lemma 3.2 for x∈ {o, r, e}. We see that G satisfies the Int. J. Algebra Comput. Downloaded from www.worldscientific.com by BILKENT UNIVERSITY on 11/28/20. Re-use and distribution is strictly not permitted, except for Open Access articles.

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hypotheses of Theorem 3.7 as P is isomorphic to P and D is the desired strongly closed set in P . It follows that Zx(K) G by Theorem 3.7. Thus, we get G = Op(G)NG(Zx(K)) as Zx(K) = Zx(K) G. Hence, NG(Zx(K)) controls strong G-fusion in P by [2, Lemma 7.1] for x∈ {o, r, e}.

We shall use the following fact in the proof of Theorem C.

Lemma 3.10. A subgroup of a p-stable group is p-stable.

Proof. Let G be a p-stable group and H≤ G. Assume that [U, h, h] = 1 where U is a p-subgroup of H and h∈ H. Now write N = NG(U ) and C = CG(U ). Let O be the full inverse image of Op(N/C) in N . Clearly, ON and O/C is a p-group. Since G is p-stable, we have h∈ O, and so h ∈ O∩H ≤ NH(U ). We see that O∩HNH(U ) as NH(U ) normalizes both O and H. Moreover, O∩ H/C ∩ H = O ∩ H/CH(U ) is a p-group as O/C is a p-group. It follows that O∩H/CH(U ) is a normal p-subgroup of NH(U )/CH(U ), and so we obtain hCH(U )∈ O ∩H/CH(U )≤ Op(NH(U )/CH(U )), that is, H is p-stable.

4. The Proofs of Theorems C, D and E

Lemma 4.1. Let P ∈ Sylp(G) and D be a strongly closed subset in P . Let H≤ G, N G and g ∈ G such that Pg∩ H ∈ Sylp(H). Then

(a) Dg∩ H is strongly closed in Pg∩ H with respect to H if Dg∩ H is nonempty.

(b) If y∈ G such that Py∩ H ∈ Sylp(H), then Dg∩ H and Dy∩ H are conjugate by an element of H.

(c) DN/N is strongly closed in P N/N with respect to G/N .

Proof. (a) Let U ⊆ Dg∩ H and h ∈ H such that Uh ⊆ Pg∩ H. Since U ⊆ Dg and Uh⊆ Pg, we see that Uh⊆ Dg as Dg is strongly closed in Pgwith respect to G. Thus, Uh⊆ Dg∩ H as Uh⊆ H.

(b) Clearly, there exists h∈ H such that (Pg∩ H)h= Py∩ H. Thus, we have (Dg ∩ H)h ⊆ Py. Since Dy is strongly closed in Py, we get that (Dg ∩ H)h Dy, and so (Dg∩ H)h ⊆ Dy∩ H. By a symmetric argument, we can reach that (Dy∩ H)h−1 ⊆ Dg∩ H, and so we get (Dg∩ H)h= Dy∩ H.

(c) Let X ⊆ DN/N and suppose that (X)y ⊆ P N/N for some y ∈ G. By an easy argument, we can find V ⊆ D such that X = V N/N.

Then we see that V N ⊆ DN and (V N)y= VyN ⊆ P N. We need to show that VyN ⊆ DN. Note that Vy = V y is a p-subgroup of P N . Since P ∈ Sylp(P N ), there exists x∈ P N such that Vy ⊆ Px. Thus, we obtain that Vy ⊆ Dx as Dx is strongly closed in Px and Vx ⊆ Dx. It follows that VyN ⊆ DxN . Write x = mn for m∈ P and n ∈ N. Note that Dx= Dmn = Dn as D is a normal set in P . It follows that DxN = DnN = DN . Consequently, VyN ⊆ DN as desired.

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LetLp(G) be the set of all p-subgroups of G. A map W :Lp(G) → Lp(G) is called a conjugacy functor if the followings hold for each U ∈ Lp(G):

(i) W (U )≤ U,

(ii) W (U )= 1 unless U = 1, and (iii) W (U )g= W (Ug) for all g∈ G.

A section of G is a quotient group H/K where K H ≤ G. Let Lp(G) be the set of all sections of G that are p-groups. A map W : Lp(G)→ Lp(G) is called a section conjugacy functor if the followings hold for each H/K ∈ Lp(G):

(i) W (H/K)≤ H/K,

(ii) W (H/K)= 1 unless H/K = 1, and (iii) W (H/K)g= W (Hg/Kg) for all g ∈ G.

(iv) Suppose that N H, N ≤ K and K/N is a p-group. Let P/N be a Sylow p-subgroup of H/N and set W (P/N ) = L/N . Then W (H/K) = LK/K.

For more information about section conjugacy functors and their properties, we refer to [3]. Note that a sufficient condition for (iii) and (iv) is the following:

whenever Q, R ∈ Lp(G) and φ : Q → R is an isomorphism, φ(W (Q)) = W (R).

Thus, the operations like ZJx, ΩZJxand Jxare section conjugacy functors for x∈ {o, r, e}.

Remark 4.2. Let G be a group, KH ≤ G and W : Lp(G)→ Lp(G) be a section conjugacy functor. The restriction of W on Lp(H/K) is a function satisfying (i), (ii) and (iii), and so W is also a conjugacy functor on Lp(H/K). Now let K = 1.

We identity this trivial quotient H/1 with H, and so instead of saying that W is a conjugacy functor onLp(H/1), we simply say that W is a conjugacy functor on Lp(H). Thus, W is also a conjugacy functor onLp(G) in particular.

Definition 4.3. Let P ∈ Sylp(G) and D be a strongly closed subset in P . Let W : Lp(G) → Lp(G) be a conjugacy functor. We define the localization of a conjugacy functor W on D as a function WD:Lp(G)→ Lp(G) with the following settings: For each p-subgroup U of P , set

WD(U ) =

W (U ∩ D) if U ∩ D = 1 W (U ) ifU ∩ D = 1

and for all V ∈ Lp(G) and x∈ G such that Vx≤ P set WD(V ) = (WD(Vx))x−1. Lemma 4.4. Let P ∈ Sylp(G) and D be a strongly closed subset in P . Let W : Lp(G)→ Lp(G) be a conjugacy functor. Then the localization of W on D, denoted by WD, is a conjugacy functor. Moreover, the equality WD = WDs holds for all s∈ G.

Proof. Since W is a conjugacy functor, it is easy to see that WD(U ) ≤ U and WD(U )= 1 unless U = 1 for each U ∈ Lp(G) by our settings.

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Now we need to show that WD(U )g = WD(Ug) for all g∈ G and U ∈ Lp(G), and indeed WD is well defined. Suppose that U, Ug≤ P for some g ∈ G. We first show that WD(U )g= WD(Ug) for this special case. Note that (U∩ D)g ⊆ Ug≤ P , and so (U ∩ D)g ⊆ Ug ∩ D as D is strongly closed in P . On the other hand, (Ug∩ D)g−1 ⊆ U ≤ P , and so (Ug ∩ D)g−1 ⊆ U ∩ D as D is strongly closed in P . By showing the reverse inequality, we obtain that (U ∩ D)g = Ug∩ D. If

U ∩ D = 1 then Ug∩ D = U ∩ Dg= 1, and so we have WD(U )g = W (U )g= W (Ug) = WD(Ug). The second equality holds as W is a conjugacy functor. Assume

U ∩ D = 1. Then we have Ug∩ D = 1 as Ug∩ D = (U ∩ D)g. It follows that WD(U )g= W (U ∩ D)g= W (U ∩ Dg) = W (Ug∩ D) = WD(Ug).

Let V ∈ Lp(G) and x, y∈ G such that Vx, Vy≤ P . Then by setting U = Vxand g = x−1y, we have Ug = Vy and WD(U )g = WD(Ug) by the previous paragraph.

It follows that WD(Vx)x−1y = WD(Vy). Then WD(Vx)x−1 = WD(Vy)y−1, and so WD is well defined. Let z∈ G and set t = z−1x. Then (Vz)t= Vx≤ P . Thus,

WD(Vz) = WD(Vzt)t−1 = WD(Vx)x−1z= (WD(Vx)x−1)z= WD(V )z which shows that WD is a conjugacy functor.

Since Ds is strongly closed in Ps, WDs is a conjugacy functor for s ∈ G by the first part. Let U ≤ P . Note that Us ≤ Ps. Assume Us∩ Ds = 1. Then WDs(U ) = WDs(Us)s−1 = W (Us)s−1 = W (U ) = WD(U ). The last equality hold as we have U ∩ D = 1 in that case. Assume Us∩ Ds = 1. Then U ∩ D =

Us∩ Dss−1 = 1. It follows that WDs(U ) = WDs(Us)s−1 = W (Us∩ Ds)s−1 = W (U ∩ Ds)s−1 = W (U ∩ D) = WD(U ). Thus, these functions agree on the subgroups of P . Let V ∈ Lp(G). Then V = Utfor some U≤ P and t ∈ G. Then we have WD(V ) = WD(Ut) = WD(U )t= WDs(U )t= WDs(Ut) = WDs(V ) by using the fact that both functions are conjugacy functors.

Remark 4.5. Although a strongly closed set is nonempty according to Defini- tion 1.1, if we take D =∅ in Definition 4.3, we get W(U ) = W (U ). Thus, we set W= W for any conjugacy functor W .

Lemma 4.6. Let P ∈ Sylp(G) and D be a strongly closed subset in P . Let KH ≤ G, N G and g ∈ G such that Pg∩ H ∈ Sylp(H). Assume W :Lp(G)→ Lp(G) is a section conjugacy functor. Then the followings hold :

(a) WDg∩H :Lp(H) → Lp(H) is a conjugacy functor. Moreover, WDg∩H is equal to the restriction of WD toLp(H).

(b) WDN/N :Lp(G/N )→ Lp(G/N ) is a conjugacy functor.

(c) W(Dg∩H)K/K :Lp(H/K)→ Lp(H/K) is a conjugacy functor.

Proof. (a) By taking the restrictions of W toLp(H), we obtain a conjugacy functor W : Lp(H) → Lp(H)(see Remark 4.2). Note that Dg∩ H is strongly closed in H∩ Pgwith respect to H if Dg∩H is nonempty by Lemma 4.1(a). Then WDg∩ H : Int. J. Algebra Comput. Downloaded from www.worldscientific.com by BILKENT UNIVERSITY on 11/28/20. Re-use and distribution is strictly not permitted, except for Open Access articles.

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