• No results found

020404 Quiz 2 Properties1) Calculate the radius of gyration for a rod of length L and radius R. The answer should beR

N/A
N/A
Protected

Academic year: 2022

Share "020404 Quiz 2 Properties1) Calculate the radius of gyration for a rod of length L and radius R. The answer should beR"

Copied!
2
0
0

Bezig met laden.... (Bekijk nu de volledige tekst)

Hele tekst

(1)

020404 Quiz 2 Properties

1) Calculate the radius of gyration for a rod of length L and radius R. The answer should be Rg2 =R2

2 +L2 12

This can be obtained by integration over a differential volume element, dV ~ rdrdl, where the distance from the center of mass is given by R2 = (r2 + l2). You will need to integrate from r = 0 to R and from l = 0 to L/2 since the distance from the center of mass to the end of the rod is L/2.

2) Give the Debye scattering function for a Gaussian polymer coil.

-Show mathematically that the low-q limit is Guinier's law -and that the high-q limit is a mass-fractal scaling law.

3) For a polymer coil the step size b is related to a physical feature, the persistence length (or Kuhn step length = 2lper) that can be measured using rheology, dynamic light scattering or static neutron scattering. The persistence length is a size where chain scaling has a transition to linear scaling at high-q.

-Sketch the neutron scattering curve for a Gaussian chain with persistence in a log I versus log q plot.

-Plot the same curve on a Kratky plot, Iq2 versus q, -and on a modified Kratky plot, Iq versus q.

4) How can the number of Kuhn units in a chain, NK, be determined from the first plot of question 3?

(2)

Answers: 020404 Quiz 2 Properties

1)

Rg2 =

∑ (

density

) (

volume

) (

Position

)

2

density

( ) (

volume

)

Consider a differential volume element, dV, for a rod, dV ~ rdrdl, and the density is constant in the rod. The squared position from the center of mass is (l2 + r2) so,

Rg2 =

r2 +l2

( )

rdr

0 L2

0

R dl

rdr

0 L2

0

R dl

=

Lr3 2 +L3r

24

  

 

0

R

dr

Lr 2 dr

0

R

=

LR4

8 + L3R2 48

  

  LR2

4

  

  = R2 2 + L2

12

2)

3)

4) R2g for the chain = NK 2lper2/3. The plot yields Rg and lper so NK can be determined. π/lper is the intercept of the modified Kratky plot or can be obtained from Rg for the persistence transition using the function obtained in question 1.

Referenties

GERELATEERDE DOCUMENTEN

The average length of time spent in prison waiting for treatment and the period of special leave increased in the researched period (influx cohort 1998 compared to influx

Although the WLC model successfully explains the elasticity of long DNA molecules, coarse-grained models of DNA at the base pair level, in which each base pair is regarded as a

In the present secondary analysis of cervical length measurement, a second cervical measurement to verify short cervical length was not necessary in patients with

We have now used three independent techniques for an improved calibration with an accuracy of approximately 7% for two of them, the interferometric method for the STM and the

• You must not create a unit name that coincides with a prefix of existing (built-in or created) units or any keywords that could be used in calc expressions (such as plus, fil,

Copyright and moral rights for the publications made accessible in the public portal are retained by the authors and/or other copyright owners and it is a condition of

29–31 However, in the context of local theories, i.e., theories in which the free energy depends only on one position, and not, as for the pressure tensor, on two positions

The results of every simulation in this research showed that the optimal value for the length scale in the Smagorinsky model is given by ∆ = min dx, dy, dz. This was tested on two