1 Homework 10 and 10,5
to be handed in: June 8, 2016
Note: the weight of this homework assignment is 1,5 times the weights of the other homework assignments.
Note: always check the web for the latest adaptations in blue in LN and BN.
Assume that the Markov process X with transition function {Pt}t, satisfies the conditions of LN Exercise 3.12. In addition, assume that E is countable, consisting only of holding points.
Assume also that E has no accumulation points.
Remind that σx = inf{t > 0 | Xt6= x}. Denote by αx the parameter of the exponentially distributed sojourn time σx in state x. Furthermore, P is the E × E transition kernel with elements P (x, y) = Px{Xσx = y}. Note that by this constructionP
y6=xP (x, y) = 1. Thus, X is a Markov jump process.
Define the following E × E matrix Q, called a q-matrix, with elements:
Q(x, y) =
−αx, y = x
αxP (x, y), y 6= x.
Suppose that there exists a function V : E → (0, ∞), and a constant c, such that:
• V is a moment function, that is, there exists an increasing sequence of compact sets Kn∈ E, n = 1, . . ., with Kn↑ ∞, n → ∞, such that limn→∞infx6∈KnV (x) = ∞.
• QV (x) =P
yQ(x, y)V (y) ≤ cV (x), x ∈ E.
Then, one can show that X is non-explosive (see Chapter 4) and that PtV (x) =X
y
Pt(x, y)V (y) ≤ ectV (x). (0.0.1)
Let ||f || = supx|f (x)|/V (x) and put
C0(E, V ) = (
f : E → R continuous
for each > 0 there exists a finite set K = K(, f ), such that |f (x)|V (x) ≤ , for x 6∈ K
)
C0(E, V ) equipped with the norm || · ||V is a Banach space.
Claim: (Pt)t is a strongly continuous semigroup on C0(E, V ).
Exercise 1 (3pts)
i) A way to prove the claim, is by first considering
PtV(x, y) = e−ctPt(x, y)V (y)
V (x) .
Show that (PtV)tis a Feller-Dynkin (sub-stochastic) transition function (on C0(E)). Use this to show that (Pt)tis a SCSG(C0(V, E)).
2
ii) Show that the generator of {Pt}t is given by Af (x) =X
y6=x
αxP (x, y)f (y) − αxf (x), f ∈ D(A),
and that f = 1{x}∈ D(A).
ii) Consider the example in LN Exercise 4.3. Check that there exists a moment function V for some constant c ≥ 0, such that QV (x) ≤ cV (x), x ∈ E. You can try functions of the vorm x 7→ V (x) = eβx, β > 0, or x 7→ V (x) =Px
i=11/i. Thus, the corresponding transition function is a SCSG(C0(V, E)).
Exercise 2 (3pts) LN Exercise 4.3.
Note: in (i), the notation Q in the exercise is meant to be the q-matrix defined above, not the generator! Then conclude what the generator is.
Exercise 3 (3pts) i) Prove Theorem 5.3.4.
ii) LN Exercise 5.7. You are not allowed to use expressions of the type Px{ηr ≥ (n + 1)t | ηr≥ nt} = .... Clearly, conditioning is on σ-algebras, not on events.
Exercise 4 (3pts) LN Exercise 5.8 (i,ii,iii).
One can e.g. solve the first part of (iii) by using that the stochastic process is the sum of two independent stochastic processes. Hence, the transition kernel corresponding to time t is a convolution of the two transition kernels corresponding to time t of the two independent processes. Of course you have to prove that the resulting generator is the sum of the respective generators. Alternatively, you can rewrite the kernel in terms of a time and space changed BM.
Exercise 5 (3pts) LN Exercise 5.11.
You may use the result of Exercise 5.10.